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2 years ago

HELP HELP HELP HELP I JUST NEED HELP FOR FINDING THE SLOPE

Mathematics

1 answer:

kogti [31]2 years ago

6 0

Answer:

The slope, -3

The y-intercept, -2

The equation (0 -(-2) ) / (1 - (-5))

Step-by-step explanation:

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Write an expression to 3(7 + 4g)

mafiozo [28]

Answer:

Step-by-step explanation:

21+12g

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3 years ago

Maths help please!!!!!! PART B ONLY

andreyandreev [35.5K]

Answer:

19.37.

Step-by-step explanation:

Integrating the function we get

x^4/4 - 5x^3/3 + x^2 + 8x

Area under the curve from x = -1 to x = 0

= (-1)^4/4 - 5(-1)^3/3 + (-1)^2 - 8

= 5.083

In a similar way we calculate area from 0 to 2

this = 10.667.

Total = 15.75.

Now we subtract 12.13 to get the area from x = 2 to x =p.

= 15.75 - 12.13 = 3.62

So total shaded area = 15.75 + 3.62

= 19.37.

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2 years ago

DO U KNOW SLOPE??? PLZ HELP

IgorLugansk [536]

To calculate slope; rise/run

Triangle ABC: run-1 rise-5 slope-5

5 rise/ 1 run (5/1)=5

Triangle DEF: run-2 rise 10 slope-5

10 rise/ 2 run (10/2)=5

B. They are equal because the two triangles are similar

7 0

2 years ago

What are the coordinates of the image after a dilation with the center at the origin and a scale factor of 2?

Marina CMI [18]

(-2, 2) (8,2) (8, -2) (-2, -2)

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3 years ago

Read 2 more answers

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago