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3 years ago

8

What is 12n^2m^4n/28n^4m^3 simplified?

2 answers:

Serggg [28]3 years ago

3 0

The answer is

288m^2n/7.

NikAS [45]3 years ago

3 0

Your answer is 288m^2n/7
I hope this helps you!

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Help needed now please

rodikova [14]

Rounded to the nearest million: 3 million
Power of ten this number is:3 times 10 6

7 0

2 years ago

39. The ratio of new houses to antique houses in a village is 4:5. If there are

jeyben [28]

Step-by-step explanation:

☄ $\underline{ \underline{ \text{Question }}}:$ The ratio of new houses to antique houses in a village is 4 : 5 . If there are 12 new houses , how many antique houses are there ?

☄ $\underline{ \underline{ \text{Solution}}} :$

✏ Let , the number of antique houses in a village be ' x ' .

Then , According to the question :

$\sf{ \frac{Number \: of \: new \: houses}{Number \: of \: antique \: houses} \: = \: \frac{4}{5}}$

⤑ $\sf{ \frac{12}{x} = \frac{4}{5}}$

Apply cross product property

⤑ $\sf{4 \times x = 12 \times 5}$

⤑ $\sf{4x = 60}$

⤑ $\sf{ \frac{4x}{4} = \frac{60}{4}}$

⤑ $\sf{x = 15}$

So, The number of antique houses in a village is 15.

$\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \bold{15}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ツ

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7 0

2 years ago

The radius of a basketball is about 3.6 times greater than the radius of a tennis ball. How many times greater is the volume of

Strike441 [17]

The basketball is 46.656 greater than the tennis ball

That is the answer

8 0

2 years ago

Aleksandr-060686 [28]

Answer:

1038

Step-by-step explanation:

you add 308 and 730

4 0

2 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago