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lapo4ka [179]
3 years ago
5

Select the equation that represents the following graph​

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

there is nothing atttached or no options given

Step-by-step explanation:

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Find the value of x. x√5=x^4​
Kaylis [27]

Answer:

x=0,\sqrt[6]{5}

Decimal form,

x=0,1.30766048......

Step-by-step explanation:

x\sqrt{5}=x^{4}

x\sqrt{5}-x^{4}=0

(take x as a common factor)

x(\sqrt{5}-x^{3})=0

So,

x=0 and \sqrt{5}-x^{3}=0

for \sqrt{5-x^{3}=0

(add x^{3} for both sides)

\sqrt{5}=x^{3}

x=\sqrt[3]{\sqrt[2]{5} } (multiply 3 by 2)

x=\sqrt[6]{5}

So,

x=0,\sqrt[6]{5}

5 0
2 years ago
Pls we only need part B to pass this subject
ikadub [295]

Answer: Weird

Step-by-step explanation: Maybe calculate all the numbers I guess.

8 0
2 years ago
Read 2 more answers
The speed of light is approximately 299,000,000 meters per second.
jek_recluse [69]

Answer:

2.99 x 10⁸ meters per second

Step-by-step explanation:

Scientific notation (also called "Standard form") is written in the form of a \times 10^n, where  1\leq a < 10  and  n is any positive or negative whole number.

To <u>convert</u> a number into <u>scientific notation</u>, move the decimal point to the left or right until there is <u>one digit before the decimal point.</u>

The number of times you have moved the decimal point is the power of 10 (n).

If the decimal point has moved to the <u>left</u>, the power is <u>positive</u>.

If the decimal point has moved to the <u>right</u>, the power is <u>negative</u>.

<u>To convert the given number to scientific notation</u>

The decimal point for the given number 299000000 is after the last zero:

⇒  299000000.

Move the decimal point 8 places to the left:  

⇒ 2.99000000

Get rid of the redundant zeros:

⇒ 2.99

Multiply by 10 to the power of the number of decimal places moved:  

⇒ 2.99 x 10⁸

Therefore, the speed of light using scientific notation is:

  • 2.99 x 10⁸ meters per second
7 0
2 years ago
ASAP ANSWER PLEASE!! Name the relationship between the two angles a and b
Irina-Kira [14]
They’re complimentary angles (add up to 90)
5 0
3 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
2 years ago
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