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3 years ago

8

Each week, Kelly pays $68.45 in federal income tax, $22.81 in state income tax, and $18.75 in other taxes. Which is the best est

imate for the payroll tax Kelly pays each month?

1 answer:

k0ka [10]3 years ago

7 0

Answer:

it is $110

Step-by-step explanation:

You might be interested in

I need helpppppppppppppppppp

notsponge [240]

Answer:

A:

9×1=9

9×2=18

9×3=27

9×4=36

9×5=45

9×6=54

9×7=63

9×8=72

9×9=81

9×10=90

B:

It goes down by 1 after multiplying a bigger number.

C:

It goes up by 1 after multiplying a bigger number.

Step-by-step explanation:

hope this helps you and have a great day

4 0

3 years ago

In ΔEFG, the measure of ∠G=90°, FG = 67 feet, and EF = 98 feet. Find the measure of ∠F to the nearest tenth of a degree.

Mama L [17]

Answer:

46.9 degrees is the answer

6 0

3 years ago

Mercury has a freezing point of -38 degrees F. Water has a freezing point of 32 degrees F. What is the difference?

Svetlanka [38]

Answer:

70

Step-by-step explanation:

Take the absolute value of both numbers. In this case, -38 and 32. So 38 and 32.

Add: 38+32

70

I think I may be wrong

5 0

3 years ago

A bag contains three red marbles, six blue marbles, and three yellow marbles. What is the probability of selecting one red marbl

Fed [463]

A bag contains three red marbles, six blue marbles, and three yellow marbles.

therefore total no. of marbles = 3 + 6 + 3 = 12

total no. of red marble = 3

therefore probablity of selecting one red marble is 3/12 = 1/4

again total no. of blue marbles is 6

therefore probability of selecting one blue marble is 6/12 = 1/2

now total probability of selecting one red ball replacing it then selecting one blue marble is. 1/4 * 1/2 = 1/8

4 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago