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Gelneren [198K]

3 years ago

6

Factoring polynomials

1 answer:

-Dominant- [34]3 years ago

7 0

1. x(2x^2-x+4)
2.-3(y-1)(y+2)
3.-(11w^2+18w-1)

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during a trip to the supermarket, Jim bought the following items bread $1.45 beans $0.88 toothpaste $2.90 milk $3.55 dog food $6

mr Goodwill [35]

15.28 I think it is the answer bc it said total so u add all the numbers. I added them and it gave me 15.28

5 0

3 years ago

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Which is the difference of 21 1/4 - 18 2/4? A:2 1/4. B:2 2/4. C:2 3/4. D:3 1/4.

seropon [69]

Answer:

2 3/4 C

Step-by-step explanation:

$(21+\frac{1}{4})-(18+\frac{2}{4})\\=21-18+\frac{1}{4} -\frac{2}{4} \\=3-\frac{1}{4} \\=\frac{12-1}{4} \\=\frac{11}{4} \\=2\frac{3}{4} \\or\\21\frac{1}{4} -18\frac{2}{4} \\=\frac{85}{4} -\frac{74}{4} \\=\frac{85-74}{4} \\=\frac{11}{4} \\=2\frac{3}{4}$

3 0

3 years ago

What is the answer to 2/3j-1/6=1/2?

Elodia [21]

It has already given you the answer.

3 0

3 years ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

3 0

3 years ago

What's the answer ?????

Tanzania [10]

The awnser is a I hope I helped you out

4 0

3 years ago

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