Factoring polynomials

Mathematics

1 answer:

-Dominant- [34]4 years ago

7 0

1. x(2x^2-x+4)
2.-3(y-1)(y+2)
3.-(11w^2+18w-1)

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Please help will give Brain!!

ss7ja [257]

The correct answer is 20

6 0

3 years ago

Add. Express your answer as a fraction. Do not include spaces in your answer. <br><br>5 1/4 + 15.5

exis [7]

Answer:

20 3/4

Step-by-step explanation:

First, add together the whole numbers:

5 + 15

= 20

Then, add the fractions and decimals together:

Convert 1/4 to a decimal, which is 0.25

Add the decimals together:

0.25 + 0.5

= 0.75

Convert this to a fraction:

0.75 = 3/4

Then, add together 20 and 3/4

20 + 3/4

= 20 3/4

4 0

3 years ago

Will someone help me with all of these, I have the answers but I’m trying check them.This is a practice assignment btw.

Ipatiy [6.2K]

We will look at the process of solving literal equations for a particular variable ( x ).

A literal equation is usually categorized by a myraid of constants that are crucial to the process which is being modeled. We solve such equation in terms of a controlling variable ( that we can choose to alter our process ).

For the following literal equations ( x ) will be the subject of variability.

$3\cdot(bx\text{ - 2ab ) = }b\cdot(x-7a)\text{ + 3ab}$

Whenever we have algebraic expressions we always refer to the rule of ( PEMDAS ).

Step 1: Solve the Parenthesis

We will solve for all the parenthesis in the equation given and write down the result:

$3bx\text{ - 6ab = bx - 7ab + 3ab }$

Step 2: Highlight and combine the like terms

All like terms are classified on the basis of their constants ( a and b ) and variable ( x ) attached. We will highlight all the like terms and take simplify them on either side of the " = " sign:

$\begin{gathered} 3bx\text{ }\text{\textcolor{#FF7968}{- 6ab}}\text{ = bx }\text{\textcolor{#FF7968}{-7ab}}\text{ }\text{\textcolor{#FF7968}{+ 3ab}} \\ 3bx\text{ - bx = 2ab} \end{gathered}$

We combined three like terms ( -6ab , -7ab , and 3ab ).

Step 3: Factorize and simplify the equation

Now we will look for any constant that is present in all the terms throughout the equation. We see that constant ( b ) is common in all the terms. Hence, we will factor ( b ) out and cancel it out from each side of the " = " sign as follows: