Triangle RMN and Triangle RQP
Triangle JHL and TriangleLKJ
Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.
To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:
1) y < 2x – 1
3<2(2)-1
3<3 Not True.
2)y ≤ 2x – 4
3≤ 2(2) -4
3≤ 0 .Not true.
3) y > 2x – 4
3> 2(2)-4
3> 0 True.
4) y < 2x + 4
3<2(2)+4
3<8 True
5) .y < 3.5x – 4
3< 3.5(2)-4
3<3 Not true
6) y < 4x – 4
3<4(2)-4
3<4 True.
Options 3 ,4 ,6 holds true for the point (2,3)
Answer:
the domain is -5 to infinity
Explanation:
f
(
x
)
=
√
x
+
5
A square root is
≥
0
so
x
+
5
≥
0
Here is a graph of the function
x
≥
−
5
g
r
a
p
h
{
√
x
+
5
[
−
10
,
10
,
−
5
,
5
]
}
Answer:
6.75 × 10^10
Step-by-step explanation: