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2 years ago

Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?

Mathematics

2 answers:

Radda [10]2 years ago

5 0

C
..............................

Advocard [28]2 years ago

3 0

Answer: The correct option is

(C) x = -2, x = 6.

Step-by-step explanation: We are given the following function :

$f(x)=3|x-2|+6~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the values of x for which f(x) = 18.

From equation (i), if f(x) = 18, we get

$f(x)=18\\\\\Rightarrow 3|x-2|+6=18\\\\\Rightarrow 3|x-2|=18-6\\\\\Rightarrow 3|x-2|=12\\\\\Rightarrow |x-2|=\dfrac{12}{3}\\\\\Rightarrow |x-2|=4\\\\\Rightarrow x-2=4,~~~~~x-2=-4\\\\\Rightarrow x=6,~~~~~~~\Rightarrow x=-2.$

Thus, the required solution is x = -2 and x = 6.

Option (C) is CORRECT.

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2 years ago

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2 years ago

Here's the question.

OleMash [197]

Answer:

The value of T₂₀ - T₁₅ is -20.

Step-by-step explanation:

Given :

>> If for an A.P, d = -4

To Find :

>> T₂₀ - T₁₅

Using Formula :

General term of an A.P.

$\star{\small{\underline{\boxed{\sf{\red{ T_n = a + (n - 1)d}}}}}}$

>> Tₙ = nᵗʰ term
>> a = first term
>> n = no. of terms
>> d = common difference

Solution :

Firstly finding the A.P of T₂₀ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{20} = a + (20 - 1) d}}}$

${\dashrightarrow{\sf{ T_{20} = a + (19)d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19 \times d}}}$

${\dashrightarrow{\sf{ T_{20} = a + 19d}}}$

${\star \: {\underline{\boxed{\sf{\pink{ T_{20} = a + 19d}}}}}}$

Hence, the value of T₂₀ is a + 19d.

$\rule{190}1$

Secondly, finding the A.P of T₁₅ by substituting the values in the formula :

${\dashrightarrow{\pmb{\sf{ T_n = a + (n - 1)d}}}}$

${\dashrightarrow{\sf{ T_{15}= a + (15 - 1) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + (14) d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14 \times d}}}$

${\dashrightarrow{\sf{ T_{15}= a + 14d}}}$

${\star{\underline{\boxed{\sf \pink{ T_{15}= a + 14d}}}}}$

Hence, the value of T₁₅ is a + 14d

$\rule{190}1$

Now, finding the difference between T₂₀ - T₁₅ :

${\dashrightarrow{\pmb{\sf{T_{20} - T_{15}}}}}$

${\dashrightarrow{\sf{(a + 19d) - (a + 14d)}}}$

${\dashrightarrow{\sf{a + 19d - a - 14d}}}$

${\dashrightarrow{\sf{a - a + 19d - 14d}}}$

${\dashrightarrow{\sf{0+ 19d - 14d}}}$

${\dashrightarrow{\sf{19d - 14d}}}$

${\dashrightarrow{\sf{5 \times - 4}}}$

${\dashrightarrow{\sf{ - 20}}}$

${\star \: \underline{\boxed{\sf{\pink{T_{20} - T_{15} = - 20}}}}}$

Hence, the value of T₂₀ - T₁₅ is -20.

$\underline{\rule{220pt}{3.5pt}}$

3 0

2 years ago

1. La asistencia a un juego de béisbol profesional fue de 4500 personas y el dinero

Elena-2011 [213]

Resolviendo un sistema de ecuaciones veremos que se vendieron 900 boletos de $15 y 3600 boletos de $10.

<h3> ¿Cuántos boletos de cada tipo se vendieron?</h3>

Primero definamos las variables:

x = número de bolteos de $10 vendidos.
y = número de bolteos de $15 vendidos.

Sabemos que se vendieron 4500 boletos, entonces:

x + y = 4500

Y se recaudo un total de $49,500, entonces:

x*$10 + y*$15 = $49,500

Entonces tenemos un sistema de ecuaciones:

Para resolver esto, primero debemos aislar una de las variables en la primer ecuación, voy a aislar x:

x = 4500 - y

Ahora reemplazamos esto en la otra ecuación:

(4,500 - y)*$10 + y*$15 = $49,500

Ahora debemos resolver estoy para y.

$45,000 - y*$10 + y*$15 = $49,500

y*$5 = $49,500 - $45,000 = $4,500

y = ( $4,500)/$5 = 900

Entonces:

x = 4500 - 900 = 3600

Se vendieron 900 boletos de $15 y 3600 boletos de $10.

Sí quieres aprender más sobre sistemas de ecuaciones:

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2 years ago

Write the equation if the line that passes through (4,5) and has a slope of m=3

andrew11 [14]

Answer:

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Step-by-step explanation:

The point-slope formula for a straight line is

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y – 5 = 3(x - 4) Remove parentheses

y – 5 = 3x - 12 Add 5 to each side

y = 3x - 7

The graph is a straight line with a y-intercept at y = -7 and a slope = 12/4 = 3.

6 0

3 years ago