Suppose you are selected for a survey but your friends persuade you to respond in a way that you dont actually agree with

the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r

zaharov [31]

The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

s(t) = -9t² + 103t + 403
time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

$s(4.499)= -9(4.499)^2 + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m$

$v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s$

when the interval = [<em>4.5, 4.501</em>]

$s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s$

The instantaneous velocity of the bottle rocket at time t=4.5;

$v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s$

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

7 0

2 years ago

Mason ran 2/3 mile in 1/3 hours. What was nasons unit rate?

Vlad [161]

2/3 miles

------------

1/3 hour

copy dot flip

2/3 * 3/1

2 miles per hour is the unit rate

Answer: 2 miles per hour

6 0

3 years ago

Read 2 more answers

You are experiencing issues when trying to transfer files between two computers using ftp. what could be the potential cause(s)

PolarNik [594]

When trying to transfer files between two computers using FTP. The issue of the server or channel may be a major reason.

<h3>What is a transfer of files using FTP?</h3>

A user can copy documents from one system to another using the File Transfer Protocol (FTP). The procedure allows data to be sent in either way seen between the consumer (the user) and also the server.

Some issues are given below.

The server cannot establish the client's IP address.
The server's inbound channel TCP 21 is banned.
The client cannot retrieve the remote IP address.
These three factors may be contributing to the inability to transmit information between two systems, as FTP doesn't even use UDP and remote ports with a large number of ports scarcely matter.