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Ahat [919]
3 years ago
8

The product of negative six and the sum of q plus two is twenty.

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

q=24

Step-by-step explanation:

2+-6=-4

20+4=24

The 24 is the sum of the 20 and to turn the negative into 0 plus the 20 equals 24

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If the sales tax rate is 8.25% how much would pay for an item that costs $24.00?
Blizzard [7]

Answer:

$25.98

Step-by-step explanation:

8.25% of 24 = 0.0825 × 24 = 1.98

1.98 + 24 = 25.98

8 0
3 years ago
A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount of gold in each bracelet is 5 grams and the amo
krok68 [10]

Answer:

The jeweler made 9 necklaces.

The jeweler made 8 bracelets.

Step-by-step explanation:

x = number of bracelets

y = number of necklaces

17 = x + y

238 = 5x + 22y

Make one of the coefficients, x, the same.

17 = x + y

Multiply this equation by 5.

85 = 5x + 5y

Subtract the equations to get rid of x.

(238 = 5x + 22y) - (85 = 5x + 5y)

(5x - 5x) + (22y - 5y) = 238 - 85

22y - 5y = 238 - 85

17y = 153

y = 153/17 = 9

The jeweler made 9 necklaces. Substitute this back into one of the equations to find x.

17 = x + y

17 = x + 9

17 - 9 = x

x = 8

238 = 5x + 22y

238 = 5x + 22(9)

238 = 5x + 198

238 - 198 = 5x

40 = 5x

x = 40/5

x = 8

The jeweler made 8 bracelets.

8 0
3 years ago
Which answer explains the correct way to move the decimal to find the product of 15.31 × 103?
cricket20 [7]
A. two places to the left
8 0
3 years ago
Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.
Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

                                                                      = 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$.

Therefore, the area of the square is given by $\text{(side)}^2$

                                                                         = $(r\sqrt 2)^2$

                                                                         $= 2 r^2$

                                                                         $= 2 (1)^2$

                                                                         $=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

7 0
3 years ago
Guys please please help me I’m begging u guys lol I need help please
Llana [10]

Answer:

What do you need help with?!?XD

Step-by-step explanation:


4 0
3 years ago
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