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Ahat [919]
3 years ago
8

The product of negative six and the sum of q plus two is twenty.

Mathematics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

q=24

Step-by-step explanation:

2+-6=-4

20+4=24

The 24 is the sum of the 20 and to turn the negative into 0 plus the 20 equals 24

You might be interested in
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
Help me fellow idiots (jk)
Ierofanga [76]

Answer:

\frac{4}{5}

8 0
3 years ago
-300 =5x-(-8x+3) step by step
cupoosta [38]

Answer:

x=  −297 /13

Step-by-step explanation:

4 0
3 years ago
What is 12- (-8) +7 in integers
Irina-Kira [14]

Answer:

12+8+7=27

Step-by-step explanation:

just normal addition

4 0
1 year ago
Help pls click on pic
Rama09 [41]

See attachment for math work and answer.

7 0
3 years ago
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