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kompoz [17]
4 years ago
8

A die has 12 faces numbered 1 through 12. On the die, 5 of the faces show prime numbers, so the theoretical probability of rolli

ng a prime number is 5/12. Which is the most likely prediction for the number of times a prime number will occur when rolling the number cube 300 times?

Mathematics
2 answers:
SOVA2 [1]4 years ago
7 0

Answer:

125 times

Step-by-step explanation:

Vanyuwa [196]4 years ago
5 0

Answer:

Step-by-step explanation:

5/12 * 300 = 125 times

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Simplify.<br><br> n 6 · n 5 ÷ n 4 · n 3 ÷ n 2 · n
trasher [3.6K]

Answer: n^{9}

Step-by-step explanation:

Given expression: n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n

The law of exponents are given by :_

a^m\cdot a^n=a^{m+n}\\\\a^m\div a^n=a^{m-n}

Using PEDMAS, first we solve division, we get

n^6\cdot n^{5-4}\cdot n^{3-2}\cdot n\\\\=n^6\cdot n\cdot n\cdot n

Now, using product law of exponent we get

n^{6+1+1+1}\\\\=n^{9}

7 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (2, –3) and (–2, 5)? 2 1/2 -1/2 -2
sergij07 [2.7K]

Answer: The slope is  -2.

Step-by-step explanation:

(2,-3)

(-2,5)

Using the two given points,  you can find the slope by finding the difference in the y coordinates and diving it by the difference in the x coordinates.

y coordinates:  -3 - 5= -8

x coordinates;  2-(-2) = 4  

Slope:  -8/ 4 = -2  

5 0
3 years ago
a goods train leaves a station at 6 pm followed by an express train which leaves at 8 pm and travels 20 km/hour faster than the
kolbaska11 [484]

Answers:

Goods train has a speed of 80 km per hour

Express train has a speed of 100 km per hour

==========================================================

Explanation:

Check out the diagram below to see the table. For now, refer to table 1.

Each row represents a different train.

We have x as the speed of the slower train (the goods train) and x+20 is the speed of the faster train (express train). These speeds are in km/hr or kph.

The y variable represents the number of hours it takes the goods train to arrive at its destination. The equation formed in the first row is 1040 = xy. This is because distance = rate*time.

Let's solve for y to get

1040 = xy

xy = 1040

y = 1040/x

We'll use this equation later.

-------------------------

The second row of table 1 has x+20 as the speed and y-2-0.6 as the time.

The "-2" represents the fact that the express train is operating for 2 hours less compared to the goods train (because the goods train had a 2 hour head start). Then the "-0.6" indicates we're taking off another 36 minutes, which is equivalent to 36/60 = 0.6 hours.

So overall, the express train is traveling for 2+0.6 = 2.6 fewer hours compared to the goods train. The express train's time value is y-2.6 hours.

With this in mind, we can form this equation for the second row

distance = rate*time

1040 = (x+20)(y-2.6)

We'll now apply substitution to replace y with 1040/x. This is valid because earlier we found that y = 1040/x

------------------------

If we apply that substitution and solve for x, we get the following

1040 = \left(x+20\right)\left(y-2.6\right)\\\\1040 = \left(x+20\right)\left(\frac{1040}{x}-2.6\right)\\\\1040 = x\left(\frac{1040}{x}-2.6\right) + 20\left(\frac{1040}{x}-2.6\right)\\\\1040 = 1040 - 2.6x + \frac{20800}{x} - 52\\\\0 = -2.6x + \frac{20800}{x} - 52\\\\x*0 = x*\left(-2.6x + \frac{20800}{x} - 52\right)\\\\0 = -2.6x^2 + 20800 - 52x\\\\-2.6x^2 - 52x + 20800 = 0\\\\

Let's now use the quadratic formula to finish things off.

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-52)\pm\sqrt{(-52)^2-4(-2.6)(20800)}}{2(-2.6)}\\\\x = \frac{52\pm\sqrt{219024}}{-5.2}\\\\x = \frac{52\pm468}{-5.2}\\\\x = \frac{52+468}{-5.2} \ \text{ or } \ x = \frac{52-468}{-5.2}\\\\x = \frac{520}{-5.2} \ \text{ or } \ x = \frac{-416}{-5.2}\\\\x = -100 \ \text{ or } \ x = 80\\\\

Ignore the negative solution because we can't have a negative speed.

The only practical solution here is x = 80

This means the goods train has a speed of 80 km/hr.

The express train's speed must be x+20 = 80+20 = 100 km/hr.

------------------------

Now to verify these answers.

If the goods train travels 1040 km and does so at a speed of 80 km/hr, then it travels for 1040/80 = 13 hours. Add this onto 6:00 PM and we arrive at 7:00 AM. This is shown in the first row of table 2 (see below).

If the express train travels 1040 km and its speed is 100 kph, then it travels for 1040/100 = 10.4 hours. This is equivalent to 10 hours, 24 minutes because 0.4 hrs = 0.4*60 = 24 min

If we start at 8:00 PM and elapse 10 hours, then we'll arrive at 6:00 AM. Add on another 24 minutes, and we get to 6:24 AM. Notice how this is 36 minutes before 7:00 AM (because 24+36 = 60). So this confirms that the express train indeed arrives 36 minutes before the goods train does, despite the goods train having that 2 hour head start.

5 0
3 years ago
The swim club rents the municipal pool for a flat fee of $500 plus a charge of $75 per swimmer during
xxTIMURxx [149]

Answer:

Y=500x+75

Step-by-step explanation:

4 0
4 years ago
PLS ANSWER WILL GIVE BRAINLIEST
Gnoma [55]

Answer:

B

Step-by-step explanation:

hope this helps

7 0
3 years ago
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