Help me please I need it
1 answer:
For this, you would’ve needed a calculator:
Because this is a right triangle, you can apply SOH CAH TOA (sin, cosin, and tangent)
You have the hypotenuse, so now you need to figure out where the angle is in relation to x and y (one at a time though).
45 degrees is opposite from x, so you would use sin (SOH) because you have the opposite and hypotenuse. This looks like:
sin(45) = opposite/6(sqrt)2
So now you want to solve for the opposite, so do 6(sqrt)2 multiplied by sin(45). Which gets you 6.
For y, you want to find adjacent so use cosin. To solve, it’s going to look like 6(sqrt)2 • cos(45) which gets you 6.
Because this is a right triangle, you can apply SOH CAH TOA (sin, cosin, and tangent)
You have the hypotenuse, so now you need to figure out where the angle is in relation to x and y (one at a time though).
45 degrees is opposite from x, so you would use sin (SOH) because you have the opposite and hypotenuse. This looks like:
sin(45) = opposite/6(sqrt)2
So now you want to solve for the opposite, so do 6(sqrt)2 multiplied by sin(45). Which gets you 6.
For y, you want to find adjacent so use cosin. To solve, it’s going to look like 6(sqrt)2 • cos(45) which gets you 6.
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Answer:
Cada parcela tendrá una extensión de 150 metros cuadrados.
Step-by-step explanation:
De acuerdo con el enunciado el huerto escolar tiene una extensión de 4 decámetros y 500 metros cuadrados.
Tengamos presente que un decámetro es igual a 100 metros cuadrados, entonces el huerto escolar tiene un área total de 900 metros cuadrados. Si dividimos esa área en seis parcelas de igual extensión, tenemos que:
Cada parcela tendrá una extensión de 150 metros cuadrados.
x + y = 114
x - y = 58
Add the equations downward:
2x + 0y = 172
2x = 172
x = 86
x + y = 114
86 + y = 114
y = 114 - 86
y = 28
Answer: The two numbers are 28 and 86.
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