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3 years ago

GEOMETRY PROBABILITY: EXPLAIN PLEASE! BRAINLIEST GIVEN !!

Mathematics

1 answer:

love history [14]3 years ago

3 0

Answer: 18%

There are 1879 people who are in the "graduate" row and "receiving aid" column. This is out of 10730 people total (bottom right corner)

The probability is 1879/10730 = 0.175 approximately which converts to 17.5% which rounds to 18%

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How would you write this as an equation?

Nat2105 [25]

Answer:c+2

Step-by-step explanation:

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3 years ago

I need help on knowing whether this is a solvable equation. Along with reasons why. HELP IF YOU CAN :))

leva [86]

To check if x = 9 is the solution, we need to replace every x with 9 and simplify

(3+x)/4 = 3

(3+9)/4 = 3

12/4 = 3

3 = 3

We get the same thing on both sides, so the last equation is a true equation. This means that the first equation is a true equation when x = 9. Therefore, the solution x = 9 is confirmed.

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3 years ago

I need help!! on 9 and 10 plzz help

Alexxandr [17]

9. 1/3+(x+20)+(x-10)+40=360 10. 1/2x+1/2x+(x-15)+(x-25)+100=540

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4 years ago

Solve the following inequality in interval notation: -(x+3)-4x<5x-2

Vikki [24]

Answer:

$(-\frac{1}{10} ,$ ∞ $)$

Step-by-step explanation:

$-(x+3)-4x$

$-x-3-4x$

$-5x-3$

$-5x-5x$

$-10x$

x > $-\frac{1}{10}$

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3 years ago

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$