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RSB [31]
3 years ago
14

How do I find zeros and multiplicities

Mathematics
1 answer:
maksim [4K]3 years ago
6 0
You can use the Ruffini's rule. The answer using this method is,

(x-3) (x+4)^2 (6 + x^2)

And you can see that the multiplicity of the zero x=-4 is 2, and the multiplicity of the zero x=+3 is 1.
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Write a own real-world scenario where the Pythagorean Theorem can be applied to find a missing piece. You can choose to write a
Ne4ueva [31]

If you are mowing a section of a lawn but want to make sure you only mow so much. Say half of a square lawn, if you know that the 2 sides of the fence are each 20 yards in length, you can apply the formula to find the distance of the diagonal. That way you know exactly how much you have mowed. draw a square, cut a diagonal through it, make the 2 sides labaled as 20 and then its 20 squared plus 20 squared = c squared. Hope this helps!

4 0
3 years ago
Read 2 more answers
How I can answer this question, NO LINKS, if you answer correctly I will give u brainliest!
chubhunter [2.5K]

Answer:

It's a direct variation condition,

hence ratio remains constant.

39 - 3

x - 4

x = 4×39/3 = 4×13 = 52 .. (for first blank space)

39 - 3

x - 10

x = 39×10/3 = 13×10 = 130 .. (for second blank space)

6 0
2 years ago
Read 2 more answers
6 m<br> 6 m<br> 3 m<br> 6 m<br> 6 m<br> 108 m)<br> 0 144 m<br> 144 m<br> 100 m<br> Other
Bad White [126]

9514 1404 393

Answer:

  (c)  144 m²

Step-by-step explanation:

The surface area can be calculated from ...

  SA = 2(LW +H(L+W))

  SA = 2((6 m)(6 m) +(3 m)(6 m +6 m))

  = 2(36 m² +(3 m)(12 m)) = 2(36 m² +36 m²) = 2(72 m²)

  SA = 144 m²

_____

<em>Additional comment</em>

The units of area are square meters (m²). The units of volume are cubic meters (m³).

5 0
3 years ago
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x,
Tomtit [17]

To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint m_{i,j,k} that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling f(x,y,z)=\cos(xyz) at the 8 points,

(1/2, 1/2, 1/2)

(1/2, 1/2, 3/2)

(1/2, 3/2, 1/2)

(3/2, 1/2, 1/2)

(1/2, 3/2, 3/2)

(3/2, 1/2, 3/2)

(3/2, 3/2, 1/2)

(3/2, 3/2, 3/2)

which are captured by the sequence

m_{i,j,k}=\left(\dfrac{2i-1}2,\dfrac{2j-1}2,\dfrac{2k-1}2\right)

with each of i,j,k being either 1 or 2.

Then the integral of f(x,y,z) over B is approximated by the Riemann sum,

\displaystyle\iiint_B\cos(xyz)\,\mathrm dV\approx\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos m_{i,j,k}\left(\frac{2-0}2\right)^2

=\displaystyle\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos\frac{(2i-1)(2j-1)(2k-1)}8

=\cos\dfrac18+3\cos\dfrac38+3\cos\dfrac98+\cos\dfrac{27}8\approx\boxed{4.104}

(compare to the actual value of about 4.159)

4 0
3 years ago
What is 6.39 rounded to the nearest tenths?
posledela
6.4 is the answer to your question 


4 0
3 years ago
Read 2 more answers
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