You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence
Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.
Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)
After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences
The confidence interval is in the form (L, U)
L = lower bound
L = dbar - t*sd/sqrt(n)
U = upper bound
U = dbar + t*sd/sqrt(n)
Answer:
14 feet
Step-by-step explanation:
4 x 3 = 12ft
4 / 2
2
2 + 12
answer is 14 ft
N= Number of visitors and $P = price $R = Revenue
<span>N = 50,000 - (P-15)*2500 </span>
<span>R = N*P = 50,000P -2,500P^2 + 15*2500P Answer (1) </span>
<span>R = 87,500P -2,500P^2 </span>
<span>dR/dP = 87,500 - 5000P = 0 for max </span>
<span>P = $17.50 for max revenue
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Answer:
y = -1/3x + 1
Step-by-step explanation:
Substitute (0,1) into equation
y= -1/3x + c
1 = -1/3 x 0 + c
1 = 0 + c
1=c
Hope this helps!