Question

(√9x^4 y)^-3 Help please

Answer 1

Remember
√xy=√x times √y
and
x^-m=1/(x^m)

simplify parenthasees firs
(√9x^4y)=√9 times √x^4 times √y=3*x^2*√y=3x^2√y
now we have

(3x^2√y)^-3=1/((3x^2√y)^3)=1/(27x^6y√y)