<h3>Roman numerals</h3>
Numbers are written as combinations of letters.
<h3>Taking into account that:</h3>
- x = 10 ⇒ (It is repeated twice)
- v = 5
- lll = 3 (To form this number, the "I", it can form itself up to 3. From 4 it changes.)
We do a sum of roman numerals
X + X + V + III = XXVIII
10 + 10 + 5 + 3 = 28
The Roman numeral <u>XXVIII</u> corresponds to the number 28 (twenty-eight).
<h2>See more about this at:</h2><h3>
brainly.com/question/6459050</h3>
Answer:
![y = -\frac{1}{3}x + 4](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B1%7D%7B3%7Dx%20%2B%204)
Step-by-step explanation:
Required
Equation of line
passes through ![(6,2)](https://tex.z-dn.net/?f=%286%2C2%29)
In an equation of the form
; the slope is ![m](https://tex.z-dn.net/?f=m)
So, by comparison;
The slope of
is: ![m =3](https://tex.z-dn.net/?f=m%20%3D3)
From the question, we understand that the required equation is perpendicular to ![y = 3x + 1](https://tex.z-dn.net/?f=y%20%3D%203x%20%2B%201)
This means that its slope is:
![m_2 =-\frac{1}{m}](https://tex.z-dn.net/?f=m_2%20%3D-%5Cfrac%7B1%7D%7Bm%7D)
So, we have:
![m_2 =-\frac{1}{3}](https://tex.z-dn.net/?f=m_2%20%3D-%5Cfrac%7B1%7D%7B3%7D)
The line equation is:
![y = m_2(x - x_1) + y_1](https://tex.z-dn.net/?f=y%20%3D%20m_2%28x%20-%20x_1%29%20%2B%20y_1)
Where:
![(x_1,y_1) = (6,2)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%20%286%2C2%29)
So, we have:
![y = -\frac{1}{3}(x - 6) + 2](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B1%7D%7B3%7D%28x%20-%206%29%20%2B%202)
![y = -\frac{1}{3}x + 2 + 2](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B1%7D%7B3%7Dx%20%2B%202%20%2B%202)
![y = -\frac{1}{3}x + 4](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B1%7D%7B3%7Dx%20%2B%204)
Answer:
there are 12 equals spaces 4 are greater than 12.
4/12 = 1/3
20 because you need to take the number and if its over 5 you go up but if its under 5 you go down
Answer:
y-intercept:20
slope:5
Step-by-step explanation: