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3 years ago

5

Miguel has 20$.be spends 7.75$ on a movie ticket,3.75$for snacks and 1.50$ for bus fare each way.How much money does Miguel have

left?

2 answers:

Vikki [24]3 years ago

7 0

Answer: $7

Step-by-step explanation:

oksian1 [2.3K]3 years ago

7 0

Answer:

$7

Step-by-step explanation:

$20.00-7.75=12.25

12.25-3.75=8.50

8.50-1.50= $7

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A printer need to make a poster that will have a total poster area of 200 in^2 and will have 1 inch margins on the sides, a 2-in

Katyanochek1 [597]

Answer:

The dimensions that will give the largest printed area of 132.1669 in^2 are

= Length x Width

= 15.20829 * 8.69045

Step-by-step explanation:

a) Data and Calculations:

Total poster area = 200 in^2

Side margins = 1 inch each

Top and bottom margins = 2 inches each

Let x = length of the full poster

then 200/x = width of the full poster

Therefore, the length of the printed area = x - 3.5

and the width of the printed area = (200/x)-2

Therefore, the Area of the Printed space = (x-3.5)((200/x)-2)

Solving for the Area (A) of the printed space, we have

A = (x-3.5)(-200/x2) + ((200/x)-2)

A = 700 -2x2

If the derivative is set to 0, we have:

0 = 700 -2x2

700 = 2x2

350 = x2

x = 18.70829 The original length

width = 10.69045

Therefore, the area of space available for printing is

15.20829 * 8.69045

= 132.1669 in^2

5 0

3 years ago

According to a survey, 62% of americans go on vacation each . two americans are chosen from a group of 100 americans. what is th

Drupady [299]

probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444

According to a survey, 62% of americans go on vacation each .

two americans are chosen from a group of 100 americans.

what is the probability that one or both of the people chosen does not go on vacation each ?

62% americans go on vacation t

hen 38% americans does not go on vacation

Total group of americans is 100

out of 100 americans 62 go on vacation and 38 does not go on vacation

probability of one go on vacation and one does not go on vacation

= 0.62*0.38

=0.2356

probability none of them go on vacation

= 0.38*0.38

=0.1444

learn more about of probability here

brainly.com/question/11234923

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6 0

1 year ago

A repair person charges $25 per hour plus and initial service charge of $30.

Norma-Jean [14]

Answer:

The repair person did 5 hours of work.

Step-by-step explanation:

155 = 25x + 30

125 = 25x

5 = x

6 0

3 years ago

Read 2 more answers

In both of the problems where would you put parentheses to make it statement true?

Darina [25.2K]

In the first one it would be (21-8)-6=7.
and in the second one it would be 21-(8-6)=19

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3 years ago

The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,

Mama L [17]

Answer:

$(a)\ P(x = 0) = 0.2725$

$(b)\ P(x \ge 1) =0.7275$

$(c)\ P(x \le 2) = 0.8948$

Step-by-step explanation:

Given

$n = 8$ --- 8 friends

$p = 15\%$ --- proportion that one-time fling

This question is an illustration of binomial probability, and it is represented as:

$P(X = x) = ^nC_x* p^x * (1 - p)^{n-x}$

Solving (a): P(x = 0) --- None has done one time fling

$P(x = 0) = ^8C_0* (15\%)^0 * (1 - 15\%)^{8-0}$

$P(x = 0) = 1* 1 * (1 - 0.15)^{8}$

$P(x = 0) = 0.85^8$

$P(x = 0) = 0.2725$

Solving (b): $P(x \ge 1)$

To do this, we make use of compliment rule:

$P(x = 0) + P(x \ge 1) =1$

Rewrite as:

$P(x \ge 1) =1 - P(x = 0)$

$P(x \ge 1) =1 - 0.2725$

$P(x \ge 1) =0.7275$

Solving (c): $P(x\le 2)$ --- Not more than 2 has one time fling

This is calculated as:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

We have:

$P(x = 0) = 0.2725$

$P(x = 1) = ^8C_1* (15\%)^1 * (1 - 15\%)^{8-1}$

$P(x = 1) = 8* (0.15) * (1 - 0.15)^7$

$P(x = 1) = 0.3847$

$P(x = 2) = ^8C_2* (15\%)^2 * (1 - 15\%)^{8-2}$

$P(x = 2) = 28* (0.15)^2 * (1-0.15)^6$

$P(x = 2) = 0.2376$

So:

$P(x\le 2) = P(x = 0) + P(x =1) + P(x = 2)$

$P(x \le 2) = 0.2725 + 0.3847 + 0.2376$

$P(x \le 2) = 0.8948$

4 0

3 years ago