All categories

3 years ago

What happens to a sample of matter when its particles lose kinetic energy?

Mathematics

1 answer:

Ivanshal [37]3 years ago

3 0

Answer:

Heat makes the particles in a solid vibrate faster, giving them more kinetic energy. Faster-vibrating particles bump into one another more often and hit each other harder. ... When a sample of solid, liquid, or gas matter cools down, it contracts. When matter cools down, its particles lose kinetic energy.

You might be interested in

A) 0,2 x 5/7 + 11/14 = ?

NemiM [27]

I hope this helps you

6 0

2 years ago

Read 2 more answers

Julian wants her rectangular garden to cover an AREA of 180 square feet what bare the LENGTHS AND WIDTHS of two possible rectang

AlekseyPX

45 because 180 divided by 2=90 and 90 divided by 2= 45 because she needs area which is length times width= area and area divided by length or width= the other

5 0

3 years ago

HELP ASAP PLEASE!!!!! <br> what is the factorization of the polynomial below -x^2-2x+48

Veronika [31]

I HOPE IT WILL HELP YOU. I DID HOW I KNOW .

8 0

2 years ago

Lúcia is using energy at a rate of 420 kilocalories (kcal) per hour (h) ice skating.

kakasveta [241]

Answer:

7000 cal/min

Step-by-step explanation:

It is mentioned that, Lucia is using energy at a rate of 420 kilo calories per hour ice skating

We know that,

1 kilo calories = 1000 calories

Using unitary method :

420 kilo calories = 420,000 calories

Also,

1 hour = 60 minutes

In this case, Lucia is using energy per 60 minutes = 420,000 calories. So,energy used by her per minute is :

$E=\frac{420000}{60} =7000 calories$

Hence, Lucia is using 7000 calories per minute.

Credit to handgunmaine: https://brainly.in/question/13030745

4 0

3 years ago

If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.

Cloud [144]

Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0

2 years ago

Read 2 more answers