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3 years ago

Is 50 a perfect square ? Explain your answer please

2 answers:

8 0

No it is not. A perfect square is a number that, if you take the square root of, gives you a whole number.
A perfect square would be : 1, 4, 9, 16, 25, 36, 49 etc.

xeze [42]3 years ago

3 0

No, 50 is not a perfect square. A perfect square is any number that can be divided by any number to get the quotient as the same number AND the quotient must be rational. When you divide 50 so that the quotient equals the divisor, you will get an irrational number. Therefore, 50 is not a perfect square.

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Dana is making a seating chart for an awards banquet. There are 184 people coming to the banquet. If 8 people can be seated at e

FromTheMoon [43]

There are 184 people
there are 8 people in each table.
184÷8= 23 tables
she need 23 tables

6 0

3 years ago

Read 2 more answers

Suppose an opaque jar contains 3 red marbles and 10 green marbles. The following exercise refers to the experiment of picking tw

kow [346]

Answer:

$\frac{5}{13}$

Step-by-step explanation:

Given,

Red marbles = 3,

Green marbles = 10,

So, the total marbles = 3 + 10 = 13,

$\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Since, here replacement is not allowed,

Thus, the probability of getting a green marble and a red marble

= first red and second green + first green second red

$=\frac{3}{13}\times \frac{10}{12}+\frac{10}{13}\times \frac{3}{12}$

$=2\times \frac{3}{13}\times \frac{10}{12}$

$=\frac{30}{78}$

$=\frac{5}{13}$

Note : The probability of getting a green marble first and a red marble second

= $\frac{10}{13}\times \frac{3}{12}$

$=\frac{30}{156}$

$=\frac{5}{26}$

4 0

3 years ago

What is the Multiplicative Property?

Norma-Jean [14]

The property where you multiply ig

3 0

3 years ago

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$