Answer:
Option A is correct answer
Answer:
C and D
Step-by-step explanation:
5^3 - 5^0 = 125 - 1 = 124, so it's not A
5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B
5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C
5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D
5 + 5^2 = 5 + 25 = 30, so it can't be E
<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
Answer:
i think it A
Step-by-step explanation:
Answer:
(9, 6)
Step-by-step explanation:
the given points are
(3, 2)
(6, 4)
so, can you see, how the sequence continues ?
I see immediately that for every 3 additional units of x we add 2 units of y.
so, yes, the next point in the sequence is
(6 + 3, 4 + 2) = (9, 6).
so, this point (or ordered pair) follows the same ratio or proportional relationship between x and y as the points already in the graph.
in other words, they are on the same line following the same slope ("y coordinate change / x coordinate change" when going from one point on the line to another).
