Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
I am assuming that we have to round the numbers to the nearest tens.
When rounding off numbers, if the number is more than half, then you round it up for example, if the number is 15 and you want to round it off, you round it up to 20. But if the number is 14 you round is down to 10
Therefore, 33 would be rounded off to 30 as 3 is less than 5 in the ones place if you get what I mean.
As for 89, you would round it up to 90 as the 9 in the ones place is more than 5.
Therefore the sum of 90 and 10 is 100.
Hope this helps!
Answer:
The perimeter of the rhombus is 218. And I think the area is 4320. Wait for more responses to be sure also for the trapezoid I used 54 as my base added them two times then multiplied it by 55 I didn't know if I had to do multiply it by 50 so after I multiplied it by 55 then divided it by two and added it to the area of the triangle in the figure. I'm not sure if I make sense but I know for sure the perimeter is 218.
Step-by-step explanation:
Answer:
Step-by-step explanation:
there are 36 squares
red takes 1 of 4 so red has 9
blue takes 1 of 3 so blue has 12
5 of 12 of the grid is yellow
Answer:
Step-by-step explanation:
