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kap26 [50]
3 years ago
15

What’s the difference between 76 and -18

Mathematics
2 answers:
Elza [17]3 years ago
6 0

Answer:

The difference between 76 and -18 is 58.

Naddika [18.5K]3 years ago
6 0

Answer:

76 is a positive number and greater than -18, and you can count this number on a chart. -18 is a negative and you cannot count this on a chart. 76 is a whole number and -18 is a integer. 76 is an integer as well

Step-by-step explanation:

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If the confidence level is decreased and the standard deviation and sample size stay the same, then the margin of error will be
Eduardwww [97]

Answer:

true

Step-by-step explanation:

If the standard deviation is increased and the sample size and confidence level stay the same, then the margin of error will also be increased

3 0
3 years ago
Solve the equation 6x +2y = 10 for y in terms of x gives what function?
Nimfa-mama [501]

Answer:

y = - 3x + 5

Step-by-step explanation:

Given

6x + 2y = 10 ( subtract 6x from both sides )

2y = - 6x + 10 ( divide all terms by 2 )

y = - 3x + 5

3 0
3 years ago
Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9
pishuonlain [190]

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

3 0
2 years ago
1.17 − 0.07a + (−3.92a) What is this ????
umka21 [38]

Answer: 17-3.99a

Step-by-step explanation:

Remove parentheses.

17- 0.07a- 3.92a17−0.07a− 3.92a

Collect like terms.

17+(−0.07a−3.92a)

Simplify.

17−3.99a

7 0
3 years ago
The histogram shows the speeds of downhill skiers during a competition. Estimate the mean of the data set displayed in the histo
Ostrovityanka [42]

Answer:

≈50.6

Step-by-step explanation:

Not sure what precision level this problem is looking for, but for right-skewed distributions, we know that the mean is going to be pulled right and therefore the mean should be larger than the median. To a high confidence level, the mean should fall between 50 and 59, or in the third column.

If a single estimation is wanted, assume the values inside each column are uniformly distributed:

\displaystyle\\\widehat{\mu}=\frac{34.5\cdot 4+...+74.5\cdot 2}{4+9+4+4+2}\approx \boxed{50.6}

8 0
2 years ago
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