Solving a compound inequality for this solution gives solution as;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
<h3>How to solve inequality problems?</h3>
Let the number of daytime cameras be x
Let the number of flash cameras be y
Thus, we have;
x + y = 20 ------(1)
Now, daytime cameras costs 2.75 dollars and the flash camera costs 4.25 dollars and you want to spend between 65 and 75 dollars, inclusive. Thus, the inequality to represent this are;
2.75x + 4.25y ≥ 65 and 2.75x + 4.25y ≤ 75
Solving the 3 compound inequalities simultaneously, we can say that the approximate values of the numbers of cameras are;
13 daytime cameras and 7 flash cameras or 7 daytime cameras and 13 flash cameras
Read more about Inequalities at; brainly.com/question/25275758
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Answer:
- 12x +15y = 4140; x + y = 300
- x = 120; y = 180
Step-by-step explanation:
The first equation is for receipts. Each x ticket generated $12 in receipts, so the first term needs to be 12x. Each y ticket generated $15 in receipts, so the second term needs to be 15y. U in this set of equations is the total number of tickets, said to be 300.
The equations are ...
12x +15y = 4140; x +y = 300
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Using the second equation to write an expression for x, we have ...
x = 300 -y
Substituting this into the first equation gives ...
12(300 -y) +15y = 4140
3600 +3y = 4140
y = (4140 -3600)/3 = 180
x = 300 -180 = 120
The number of tickets sold is ...
$12 tickets -- 120
$15 tickets -- 180
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You might want to notice that the equation we ended up with:
4140 -12(300) = 3y
is equivalent to this "word solution." This can be done in your head; no equations required.
If all the tickets sold were $12 tickets, the revenue would be $3600. The revenue is $540 more than that. Each $15 ticket generates $3 more revenue than a $12 ticket, so to have $540 more revenue, we must have 540/3 = 180 $15 tickets.
Answer:
8.8 Kilograms
Step-by-step explanation: