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Eduardwww [97]
3 years ago
8

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t

han the width, x, which interval can be the possible widths?
Mathematics
1 answer:
JulijaS [17]3 years ago
3 0
LW < = A (thats less then or equal to)
W = x
L = x + 18
A = 175

x(x + 18) < = 175
x^2 + 18x - 175 < = 0
(x + 25)(x - 7) < = 0

x + 25 < = 0
x < = -25.....extraneous solution...not ur answer

x - 7 < = 0
x < = 7 <==

so anything less then or equal to 7 can be a possible width
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