All categories

3 years ago

P(x)=2x^3+5x^2-2x-5 find the zeros

Mathematics

1 answer:

pav-90 [236]3 years ago

7 0

Answer:

x-5=0\\x=5

Step-by-step explanation:

You might be interested in

Evaluate the expression when x-3 4x2 - 14x + 4

Lady_Fox [76]

Answer:

Step-by-step explanation:

Evaluate 4 x^2 - 14 x + 4 where x = -3:

4 x^2 - 14 x + 4 = 4×(-3)^2 - -3×14 + 4

(-3)^2 = 9:

4×9 - 14 (-3) + 4

4×9 = 36:

36 - 14 (-3) + 4

-14 (-3) = 42:

36 + 42 + 4

| 1 |

| 4 | 2

| 3 | 6

+ | | 4

| 8 | 2:

Answer: 82

6 0

2 years ago

Lori entered a 100 km race. A Kilometer is about of a mile. About how many miles ling is the race?

djverab [1.8K]

Answer:

About 62.1371

Step-by-step explanation:

6 0

3 years ago

Is 0 less than or greater than -2

Anastaziya [24]

Answer:

0 is greater

Step-by-step explanation:

When comparing the values of two numbers, you can use a number line to determine which number is greater.

5 0

2 years ago

Read 2 more answers

What is the intercept to this graph, please??

velikii [3]

Answer:

there is no intercept

Step-by-step explanation:

5 0

3 years ago

Which is equivalent to (2^-3)^4 1/2^12 2 -2^12 1/2^7

sleet_krkn [62]

Answer:

The answer is First option

1/2^12 .

$\frac{1}{2^{12} }$

Step-by-step explanation:

Given:

(2^-3)^4

i.e

$(2^{-3} )^{4}$

To Find:

$(2^{-3} )^{4}=?$

Solution:

Law of Indices

$(x^{a}) ^{b} =x^{a\times b}\\and\\x^{-1}=\frac{1}{x}$

Using the above Property we get

∴ $(2^{-3} )^{4}=2^{-3\times 4} \\\\ (2^{-3} )^{4}=2^{-12} \\\\(2^{-3} )^{4}= \frac{1}{2^{12} }$

The answer is First option

1/2^12 .

$(2^{-3} )^{4}=\frac{1}{2^{12} }$

6 0

3 years ago