Answer:
The linear equation
and Erin can pick
apples per hour if she maintains a constant rate.
Step-by-step explanation:
To find the linear equation of the relationship from the graph.
We have to find the coordinates .
Let say
and ![(x_1,y_1)=(2,100)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%282%2C100%29)
Here
variable is the time in hour and
variable is the number of apples.
To find linear equation we have to find the slope (m) of the line by using point-slope form.
![m=\frac{y_1-y}{x_1-x}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_1-y%7D%7Bx_1-x%7D)
So,
![m=\frac{100-50}{2-1}=50](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B100-50%7D%7B2-1%7D%3D50)
The the linear equation will be.
![y=50(x)](https://tex.z-dn.net/?f=y%3D50%28x%29)
Number of apples Eric pick in an hour is
.
By plugging the value of
in the equation we can find the number of apples picked by Erin per hours subsequently
for second hour.
In each hour she picks
apples.
Linear equation is
and number of apples picked by Eric in an hour is
.
The slope is 5
the y intercept is -4
slope intercept form is: y=mx+b
M is always the slope, b is the y intercept.
Hope I helped!
having all the necessary or appropriate parts:
Answer: The machine depreciates during the fifth year by $4000.
Step-by-step explanation:
Given: The resale value of a certain industrial machine decreases over a 8-year period at a rate that changes with time.
When the machine is x years old, the rate at which its value is changing is 200(x - 8) dollars per year.
Then, the machine depreciates A(x) during the fifth year as
![A(x) =\int^{5}_1200(x - 8)\ dx\\\\=200|\frac{x^2}{2}-8x|^{5}_1\\\\=200[\frac{5^2}{2}-\frac{1^2}{2}-8(5)+8(1)]\\\\=200 [12-32]\\\\=200(-20)=-4000](https://tex.z-dn.net/?f=A%28x%29%20%3D%5Cint%5E%7B5%7D_1200%28x%20-%208%29%5C%20dx%5C%5C%5C%5C%3D200%7C%5Cfrac%7Bx%5E2%7D%7B2%7D-8x%7C%5E%7B5%7D_1%5C%5C%5C%5C%3D200%5B%5Cfrac%7B5%5E2%7D%7B2%7D-%5Cfrac%7B1%5E2%7D%7B2%7D-8%285%29%2B8%281%29%5D%5C%5C%5C%5C%3D200%20%5B12-32%5D%5C%5C%5C%5C%3D200%28-20%29%3D-4000)
Hence, the machine depreciates during the fifth year by $4000.
Answer:
You got them both right, no other choices need to be selected.
Step-by-step explanation:
Both the choices you have put yes to, will give an answer equal to 32.
Since they want us to find the full amount of students in his class, and 20 is 4 more than half the class 20-4=16 and then 16 x 2 is 32
1/2m+4=20 is correct because, if you move the 4 across the equal sign it become a negative and will be subtracted from the 20 therefore becoming 16. 1/2m=16. Now left with only the 1/2m we must multiply by 2 because 1/2 is a fraction and mutipliting it by 2 will allow us to get 1/2 to equal 1 and m by itself.
1/2m*2=1m
1m=16*2 Keep in mind you must do the same to both sides so the 16 is multiplied as well.
4th option: Same thing different order
Just send 1/2m over equal sign and 4 over the equal sign to trade places. and you will have 1/2m=16