2 years ago

Can anyone help with the last problem about The Difference Quotient of a Function

Mathematics

1 answer:

Marysya12 [62]2 years ago

3 0

Answer:

tbh i really dont know

Step-by-step explanation:

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Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

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$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
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||v1||=\sqrt{(-6)^2+4^2}\\
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\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
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