All categories

3 years ago

Can someone help with this please

Mathematics

1 answer:

qwelly [4]3 years ago

6 0

B

= 6m^4n^6

c

2/x^-4
= 2x^4

e
3^4 w^-8
= 81 w^-8
= 81/w^8

f
m^-3
= 1/m^3

You might be interested in

Please please help me

svetlana [45]

Answer:

here is the equation : y= 3x+10
table: o miles would be $10, 5 miles would be $25, 10 miles would be $40.

Step-by-step explanation:

for the second part you can use the equation above and substitute the value of x in the equation to find y.

explanation: 3 dollars per mile so 5 miles costs 15 dollars but since there is a flat fee of 10 dollars it would total to 25 dollars.

3 0

3 years ago

AC=3x+3, AB=-1+2x, and BC=11 find x

Nikolay [14]

Answer:

the Value of x is 7.

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

kondaur [170]

Answer: A. profit of $4500

<u>Step-by-step explanation:</u>

r(x) = x² + 6x + 10

- <u>c(x) = x² - 4x + 5</u>

(r - c)(x) = 10x + 5

(r - c)(4) = 10(4) + 5

= 40 + 5

= 45

(r - c)(x) represents the profit (in hundreds of dollars) in x months

(r - c)(4) represents the profit (in hundreds of dollars) in 4 months

So, the new store will have a profit of $4500 in 4 months

3 0

3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago

You have a part-time job. You earn $7.75 per hour. If you work 20 hours

katovenus [111]

Answer:

F. $155

Step-by-step explanation:

For this problem we simply need to multiply the base hourly pay by the amount of hours worked to find the straight-time pay for each week.

$7.75 * 20 = $155

Thus, your weekly pay will be $155.

Cheers.

4 0

3 years ago

Read 2 more answers