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alexgriva [62]
4 years ago
11

Given that BE=6, CE=6,and FE measures 5 morethan DE, find the lengthof DE.​

Mathematics
1 answer:
katen-ka-za [31]4 years ago
4 0

Answer:

DE = 4 units.

Step-by-step explanation:

By the chord intersection theorem:

BE * CE = DE * FE

But FE = DE + 5 so:

BE * CE = DE * (DE + 5)

6 * 6 = DE^2 + 5DE

DE^2 + 5DE  - 36 = 0

(DE + 9)(DE - 4) = 0

So DE = -9 or 4

It can't be negative so DE = 4.

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3 years ago
What is the solution for -10 -19<br> x -1<br> x &lt; -1
Natali [406]

Answer:

x=-1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the equation of a circle with center of (4,2) passing through the point (7,2)
attashe74 [19]

Answer:

(x-4)^2 + (y-2)^2 = 3^2

or

(x-4)^2 + (y-2)^2 = 9 (simplified if needed)

Step-by-step explanation:

-Equation of a circle is:

(x-h)^2+(y-k)^2=r^2 where the center is (h, k) and the radius is r^2.

-Place the center and the point onto that equation:

(7-4)^2+(2-2)^2=r^2

-Then, you solve:

(7-4)^2+(2-2)^2=r^2

(3)^2+(0)^2=r^2

9 +0=r^2

9=r^2

\sqrt{9} =\sqrt{r^2}

3=r

-So, the result is:

(x-4)^2+(y-2)^2=3^2

or

(x-4)^2+(y-2)^2=9 (simplified if needed)

3 0
3 years ago
Network poll what do you usually do after school? sport/club practice 28% nap 11% work 6% homework 17% game 14% eat a snack 13%
Sav [38]
About
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1133 people nap
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4 0
3 years ago
Does the given equation of line form parallel lines or not
malfutka [58]

k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1\cdot m_2=-1\\\\k\ ||\ l\iff m_1=m_2

k:x+4y=10\ \ \ |-x\\\\4y=-x+10\ \ \ \ |:4\\\\y=-\dfrac{1}{4}x+\dfrac{10}{4}\to m_1=-\dfrac{1}{4}\\\\l:3x-2y=5\ \ \ \ |-3x\\\\-2y=-3x+5\ \ \ \ |:(-2)\\\\y=\dfrac{3}{2}x-\dfrac{5}{2}\to m_2=\dfrac{3}{2}

m_1\neq m_2\to\text{ no parallel}\\\\m_1\cdot m_2=-\dfrac{1}{4}\cdot\dfrac{3}{2}\neq-1\to\text{ no perpendicular}

Answer: NOT PARALLEL

5 0
4 years ago
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