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Sholpan [36]
3 years ago
7

Find the circumference and area of a circle with radius 6 m. Use the value 3.14.

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Answer:

Area = 3.14 * 62 = 36 * 3.14

Circumference = 3.14 * (2 * 6) = 3.14 * 12

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V=1/3Ah<br>make h the subject of the formula when A=15 and h= 7​
ella [17]

Answer:

v =  \frac{1}{3} \times 15 \times 7 \\ 5 \times 7 \\  = 35

3 0
3 years ago
In each one section there are 27 student and there are 17 section how many students are in total ​
stiks02 [169]

Answer:

459 students.

Explanation:

Since you are given the number of how many students are in each section, simply multiply to find the total answer.

27 x 17 = 459

There are 459 students.

8 0
3 years ago
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SHARON MAKES $32 FOR 2 HOURS.
zhannawk [14.2K]

Answer:

See below.

Step-by-step explanation:

$32/( 2 hours) = $16/hour

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3 years ago
The perimeter of a college basketball court is 96m and the length is 14me more than the width. what are the dimesions?​
Margaret [11]

Step-by-step explanation:

let width =x

length=x+14

....

perimeter=96=2*(L+W)

96=2*(X+X+14)

96=4x+28

96-28=4x

68=4x

/4

68/4=x

17=x the width

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....

Check

17+17+31+31=96

I hope it's helpful!

8 0
3 years ago
Question 1: The diagonal of a rectangle, with base x, remains at a fixed
kramer

We have that The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is  the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle   is mathematically given

as

r^2=h^2+x^2

With r=3

Therefore

dx/dt=8cm/s

Hence

2rdr/dt=2hdh/dt+2xdx/dt\\\\\dh/dt=\frac{-x}{r^2-x^2}dx/dt

We  have

dh/dt=-2/\sqrt{5}(8)\\\\dh/dt=-7.2cm/s

Therefore

The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

For more information on this visit

brainly.com/question/23366835

4 0
3 years ago
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