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3 years ago

11

The third-grade classes going on a field trip by bus to the museum. The bus leaves the school at 9:45 AM. The bus ride takes 47

minutes. What time does the bus arrive at the museum

1 answer:

Minchanka [31]3 years ago

6 0

9:45 plus 47 minutes equals 10:32

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3 years ago

WILL GIVE BRAINLIST please help i dont remember this

sergiy2304 [10]

Answer:

(3,5)

Step-by-step explanation:

Here we are asked to find the reflection of Point P(-1,5) along the line represented by x=1

Please refer to the image attached with answer.

We have point P (-1,5) , the line x=1 and the Point R which is the reflection of P across x=1

now we can see that P is 2 units towards left of the line x=1. hence its reflection across x=1 will be 2 units away towards right of line. 2 units away , the x coordinate will be 1+2 = 3

Hence the x coordinate is 3 and y coordinate remains the same. Hence the coordinates of R will be (3,5)

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3 years ago

A particle moves along the curve below. y = √ 8 + x 3 As it reaches the point ( 1 , 3 ) , the y -coordinate is increasing at a r

Dmitry [639]

Answer:

<em>The x-coordinate is changing at 10 cm/s</em>

Step-by-step explanation:

<u>Rate of Change</u>

Suppose two variables x and y are related by a given function y=f(x). If they both change with respect to a third variable (time, for instance), the rate of change of them is computed as the derivative using the chain rule:

$\displaystyle \frac{dy}{dt}=\frac{dy}{dx}\cdot \frac{dx}{dt}$

We have

$y=\sqrt{8+x^3}$

Or, equivalently

$y^2=8+x^3$

We need to know the rate of change of x respect to t. We'll use implicit differentiation:

$\displaystyle 2y\cdot \frac{dy}{dt}=3x^2\cdot \frac{dx}{dt}$

Solving for dx/dt

$\displaystyle \frac{dx}{dt}=\frac{2y\cdot \frac{dy}{dt}}{3x^2}$

Plugging in the values x=1, y=3, dy/dt=5

$\displaystyle \frac{dx}{dt}=\frac{2(3)\cdot 5}{3\cdot 1^2}=10$

The x-coordinate is changing at 10 cm/s

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3 years ago