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3 years ago

A fossil of an adult dinosaur food measures 69 cm.About how long would its hind leg bone have been?

Mathematics

1 answer:

hammer [34]3 years ago

8 0

5,5?
I dont know if this is it but I hope it helps.
btw I wrote 5 ft five XD ty bye

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What’s the opposite of SÍ (in Spanish)

exis [7]

Answer:

the answer is "no" it is litterally the same in english

Step-by-step explanation:

Si in spanish is yes and no in spanish is no

3 0

3 years ago

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Elect the correct answer. What are the solutions of this quadratic equation?

zvonat [6]

Answer:

Rewrite equation as:

x^2 + 2x +2 =0

a = 1 b = 2 c = 2

x = (-b +- sqr root (b^2 -4ac)) / 2a

x = (-2 +- sqr root (2^2 - 4*1*2) ) / 2

x = (-2 +- sqr root (4 - 8) ) / 2

x = (-2 + sqr root (-4) ) / 2

x = -1 +- i

Step-by-step explanation:

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3 years ago

Recall the equation for a circle with center ( h , k ) and radius r . At what point in the first quadrant does the line with equ

astraxan [27]

Answer:

The Point in the first quadrant is $(\sqrt[2]{2.0268} ,6.559)$ .

Step-by-step explanation:

Since

we know the general equation of the circle whose center is at (h,k) and radius is r that is

$(x-h)^2+(y-k)^2 =r^2$

we have given center is (0,3) and radius is r= 4

substituting in the general equation of the circle we get

$x^2 +(y-3)^2 = 16$

Now substituting the y= 2.5x + 3 in the above equation we get

$x^2 +(2.5x + 3-3)^2 = 4^2$

$x^2 +6.25x^2 = 16$

here subtracting 16 from both sides and also perform addition

we get

$7.25x^2 = 16$

dividing both sides by 7.25 we get

$x^2 =2.2068$

taking square root both sides we get

$x= \frac{+}{-}\sqrt[2]{2.0268}$

but we need positive value of x because both x and y are positive in the first quadrant

that is

$x= \sqrt[2]{2.0268}$

substituting this into the given equation of the line we get

y = 2.5( $\sqrt[2]{2.0268}$ )+3

y = 6.559

so the point in the first quadrant is ( $\sqrt[2]{2.0268}$ ,6.559)

that is required

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4 years ago

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Halley’s comet has an elliptical orbit with the sun at one focus. The eccentricity of the orbit is approximately 0.97. The lengt

kherson [118]

so the sun is one of the foci, and we have an eccentricity of 0.97. So the ellipse will look more or less like the picture below.

$\bf \textit{ellipse, horizontal major axis}\\\\\cfrac{(x- h)^2}{ a^2}+\cfrac{(y- k)^2}{ b^2}=1\qquad \begin{cases}center\ ( h, k)\\vertices\ ( h\pm a, k)\\c=\textit{distance from}\\\qquad \textit{center to foci}\\\qquad \sqrt{ a ^2- b ^2}\\eccentricity\quad e=\cfrac{c}{a}\end{cases}\\\\-------------------------------\\\\\begin{cases}h=0\\k=0\\a=35.88\\e=0.97\end{cases}\implies \cfrac{(x-0)^2}{35.88^2}+\cfrac{(y-0)^2}{b^2}=1\\\\-------------------------------$

$\bf e=\cfrac{c}{a}\implies 0.97=\cfrac{c}{35.88}\implies \boxed{34.8036=c} \\\\\\ c=\sqrt{a^2-b^2}\implies b=\sqrt{a^2-c^2}\implies b=\sqrt{35.88^2-34.8036^2} \\\\\\ \boxed{b\approx 8.72}\\\\ -------------------------------\\\\ \cfrac{(x-0)^2}{35.88^2}+\cfrac{(y-0)^2}{8.72^2}=1\implies \cfrac{x^2}{1287.3744}+\cfrac{y^2}{76.0384}=1$

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4 years ago

Calculate radius from 27 circumference

natali 33 [55]

The radius is 4.29718

4 0

3 years ago