What is the respond for 4(b-6)+19

1 answer:

4 0

So I think you’re asking for the solution to the equation mentioned.

The answer would be 4b-5

Explanation:
Steps:

4(b-6)+19

4b-24+19

4b-5 (Answer)

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Cos(theta)= -.9041, 180degress< theta <270degress

AVprozaik [17]

Answer:

$\theta=205.298^o$

Step-by-step explanation:

We know

$cos\theta=-.9041$

in the third quadrant $180^o$

We use a scientific calculator to find the inverse cosine of -0.9041 to find

$\theta=154.702^o$

Since this angle is not in the required quadrant we must find the other angle who has the same cosine. The required angle is equidistant from the found value from the 180 degrees angle, so our solution is

$\theta=180^o+(180^o-154.702)=205.298^o$

7 0

3 years ago

If I saved up $10 every 2 weeks, how much would I have saved in a year? Please help, thank you!

brilliants [131]

I believe there’s 52 weeks in a year besides leap year so it would be 52 divided by 2 times 10 and you’d have your answer

4 0

2 years ago

Read 2 more answers

I need help.. A diameter of a circle has endpoints p(-10, -2) and q(4, 6)

Phoenix [80]

A: The center is the mid point of the diameter. So, the center of the circle will be the midpoint of points P and Q. The coordinates of the midpoint are the averaged coordinates of the endpoints.

So, the x-cooardinate of the center is the average of the x-coordinates of P and Q:

$C_x = \dfrac{P_x+Q_x}{2}=\dfrac{-10+4}{2}=\dfrac{-6}{2}=-3$

Try to do the same thing with the y coordinates, and you'll get the y-coordinate $C_y$ . This first part will be over, because the circle will be point

$C=(C_x,C_y)$

B: The radius is exactly half the diameter. So, we find the length of the diameter, and we divide it by 2. To find the length of the diameter, we use the standard formula for the distance between two points:

$d=\sqrt{(P_x-Q_x)^2+(P_y-Q_y)^2}=\sqrt{(-10-4)^2+(-2-6)^2}=\sqrt{260}=2\sqrt{65}$

Divide this length by 2 and you'll get the radius.

C: At this point, we have both the radius and the coordinates of the center. The equation of the circle depends on these two parameters, and it is

$(x-C_x)^2+(y-C_y)^2=r^2$

Substitute $C_x$ and $C_y$ with the coordinates of the center (found in point A.) and $r$ with the radius (found in point B.) and you'll have the equation of the circle.