why should people be concerned about continental drift and plate tectonics? what values does it have for the public?

1 answer:

3 0

Humans should be concerned with continental drift and plate tectonics because these forces have a major impact on the environment and also lead to major natural disasters. Shifts in tectonic plates lead to earthquakes which can also cause things like typhoons or tsunamis. Therefore, begin knowledgeable about the locations of fault lines and areas with the high potential for natural disasters as a result of shifting plates is very important.

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1.How does the amount of carbon dioxide in the air in Alaska today compare to the amount 200 years ago? (2 points)✓It is about 3

Marizza181 [45]

Answer:

It is about 30 percent more

Explanation:

Global Warming is the reason for the change in the amount of carbon dioxide in the air from 200 years ago. Alaska has been warming nearly twice as quick as the global scale. Alaska in the past few years has been recording some of its warmest temperatures, with a new marking of snow records in various places.

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4 years ago

In the convection currents, where is there hifhhigh density

zhenek [66]

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3 years ago

. If the fastest passenger aircraft can fly 0.45 km/s (1000 mph), how long would it take to reach the sun? The galactic center?

nadezda [96]

Answer:

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The passenger aircraft would take $1.733\times 10^{10}$ years to reach the gallactic center.

Explanation:

The distance to the sun from the Earth is approximately equal to $1.496\times 10^{8}\,km$ , if the passenger travels at constant speed, then the time needed to reach the sun is calculated by the following kinematic formula:

$\Delta t = \frac{s}{v}$ (1)

Where:

$s$ - Travelled distance, measured in kilometers.

$v$ - Speed of the passenger aircraft, measured in kilometers per second.

$\Delta t$ - Travelling time, measured in seconds.

If we know that $s = 1.496\times 10^{8}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is:

$\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }$

$\Delta t = 3.324\times 10^{8}\,s$

$\Delta t = 3847.736\,days$

$\Delta t = 10.542\,years$

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to $2.460\times 10^{17}\,km$ . If the passenger travels at constant speed and if we know that $s = 2.460\times 10^{17}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is: