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denpristay [2]
3 years ago
6

what is the x-intercept of the line with the equation 4x 2y = 12? a. (0, 6) b. (0, 3) c. (6, 0) d. (3, 0)

Mathematics
1 answer:
Georgia [21]3 years ago
7 0
If you would like to find the x-intercept of the line with the equation 4x + 2y = 12, you can do this using the following steps:

4x + 2y = 12
y = 0
4x + 2 * 0 = 12
4x = 12
x = 12/4 = 3

(x, y) = (3, 0)

The correct result would be <span>d. (3, 0).</span>
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One person can do a certain job in ten minutes, and another person can do the same job in fifteen minutes. How many minutes will
Alexxandr [17]
A can do 1 job in 10 min. means 1/10 job per min.
B can do 1/15 job per min.

together A&B can do 1/10+1/15 =1/6 job per min.

1/6 job they spend 1 min
1 spend 1x1/(1/6) = 6 min
4 0
3 years ago
Find the equation of the line graphed below. Write the equation in the form y = mx + b and identify m and b m = b =
Alla [95]

ANSWER:

m = -3/4

b = -3

y=-\frac{3}{4}x-3

STEP-BY-STEP EXPLANATION:

We have that the equation in its slope-intercept form is the following:

\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}

We calculate the slope as follows:

m=\frac{y_2-y_1}{x_2-x_1}

To calculate the slope we use the intercepts that are (-4, 0) and (0, -3), we replace:

m=\frac{-3-0}{0-(-4)}=\frac{-3}{4}=-\frac{3}{4}

Now, the value of b would be -3, since the y-intercept is (0,-3), therefore, the equation would be:

y=-\frac{3}{4}x-3

6 0
1 year ago
If the length of the minor axis of an ellipse is 6 units and the length of the major axis is 10 units, how far from the center a
Sedbober [7]

The distance from the center to where the foci are located exists 8 units.

<h3>How to determine the distance from the center?</h3>

The formula associated with the focus of an ellipse exists given as;

c² = a² − b²

Where c exists the distance from the focus to the center.

a exists the distance from the center to a vertex,

the major axis exists 10 units.

b exists the distance from the center to a co-vertex, the minor axis exists 6 units

c² = a² − b²

c² = 10² - 6²

c² = 100 - 36

c² = 64

c = \sqrt{64}

c = 8

Therefore, the distance from the center to where the foci are located exists 8 units.

To learn more about the Pythagorean theorem here:

brainly.com/question/654982

#SPJ4

3 0
1 year ago
What is true about the solutions of a quadratic equation when the radicals of the quadratic formula is a positive number that is
seraphim [82]
When the radicals of the quadratic equation (also known as the discriminant) is a positive number that is not a perfect square, the equation has 2 irrational roots
5 0
4 years ago
Lim x—&gt; -2 <br> sqrt(3x+10) -2/ x+2
snow_lady [41]

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}

Rationalize the numerator:

\dfrac{\sqrt{3x+10}-2}{x+2}\cdot\dfrac{\sqrt{3x+10}+2}{\sqrt{3x+10}+2}=\dfrac{(3x+10)-4}{(x+2)(\sqrt{3x+10}+2)}=\dfrac3{\sqrt{3x+10}+2}

where the x+2 factors in the numerator and denominator cancel. Then the limit is

\displaystyle\lim_{x\to-2}\frac{\sqrt{3x+10}-2}{x+2}=\lim_{x\to-2}\frac3{\sqrt{3x+10}+2}=\frac3{\sqrt4+2}=\boxed{\frac34}

8 0
3 years ago
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