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sleet_krkn [62]

3 years ago

15

3y=4x+15 and 9x+12y=12 are perpendicular,parallel or neither

2 answers:

slavikrds [6]3 years ago

8 0

Answer:

These two lines are perpendicular.

Step-by-step explanations:

In order to find this, we need to compare slopes. If they are the same it is parallel, if it is opposite and reciprocal then it is perpendicular, and if it is neither of those things then it is neither. To find the slopes, we need to solve both equations for y.

3y = 4x + 15

y = 4/3x + 5

------------------

9x + 12y = 12

12y = -9x + 12

y = -3/4x + 1

The slopes of 4/3 and -3/4 are opposite and reciprocal. Therefore it is perpendicular.

xxTIMURxx [149]3 years ago

4 0

These two linear equations are <em>perpendicular</em>, because 3y=4x+15 has a slope of $\frac{4}{3}$ and 9x+12y=12 has a slope of - $\frac{3}{4}$ , and since those two fractions have exact opposite slopes (flip the denominator and numerator and multiply by -1), they are perpendicular.

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ira [324]

Answer:

i think the scale factor is 3:2

Step-by-step explanation:

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Nana76 [90]

Answer:

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3 years ago

Please answer one question asap <br>A(-4,3) B(2,-1) D(-4,-1) C(2,-5)

Leni [432]

Answer:

Step-by-step explanation:

Vertices of the given quadrilateral are A(-4, 3), B(2, -1), C(2, -5) and D(-4, -1)

Since, slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

Slope = $\frac{y_2-y_1}{x_2-x_1}$

Slope of AB = $\frac{3+1}{-4-2}$

= $-\frac{2}{3}$

Slope of AD = $\frac{3+1}{-4+4}$

= Not defined (Parallel to y-axis)

Slope of DC = $\frac{-5+1}{2+4}$

= $-\frac{2}{3}$

Slope of BC = $\frac{-1+5}{2-2}$

= Not defined (Parallel to y-axis)

Slope of AB = slope of DC = $-\frac{2}{3}$

Slope of BC = slope of AD = Not defined (parallel to y-axis)

As per property of a parallelogram,

"Opposite sides of a parallelogram are parallel and equal in measure"

Therefore, ABCD is a parallelogram.

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