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alexdok [17]
3 years ago
14

which quadrilateral always has two pairs of parallel sides, four right angles, and four congruent sides

Mathematics
2 answers:
gayaneshka [121]3 years ago
3 0
A square

The two sets of sides across from each other are parallel.

All angles are right.

All sides are equal.
Nuetrik [128]3 years ago
3 0

Answer:

I believe the answer is a square.

Step-by-step explanation:

I came to this conclusion by breaking it down.

A square has two pairs of parallel sides.

A square also has four right angles.

A square also has four congruent (same shape and size) sides.

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*NEED HELP!*
Vlad1618 [11]

Answer and Step-by-step explanation:

Hello!~

Let's~answer~your~question!

So,~for~this~equation,~we~need~to~use ~the~distributive~property~of ~multiplication.~but,before~we~start~to~solve  this~equation,~let's~get~to~know~what

distributive ~property ~of~multiplication~means!

<em><u /></em>

<em><u>Distributive property of multiplication :</u></em>  

Distributive~property~of~multiplication~states~thatwhen~a~~number~is~multiplied

by~the ~sum ~of~ two~ numbers, the~ first~ number ~can~ be ~distributed ~to both ~of~those numbers~and~multiplied~by~each~of~them separately.

→ a*(b+c)=a*b*+~a*c  

<em><u>Now, that we know what it means let's apply it in our equation:</u></em>

<em><u /></em>(2*x)+(2*7)=36<em><u /></em>

<em><u /></em>

<em><u>Now, we simplify:</u></em>

<em><u /></em>2x+14=36<em><u /></em>

<em><u /></em>

<em><u>Divide both sides by 2 in the equation:</u></em>

<em><u /></em>\frac{2x+14}{2} =\frac{36}{2}<em><u /></em>

<em><u /></em>

<em><u>Simplify :</u></em>

<em><u /></em>x+7=18<em><u /></em>

<em><u /></em>

<em><u>Thus, the first correct step is option B,</u></em>

<em><u /></em>then~comes,~option~"A"~then,~option~"F"~as~shown~above The~remaining~options~are~not~enough~information~to~solve~the~given equation:(x + 7) = 36.

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3 years ago
For angle theta with the point (15, -8) on its terminating side, what is the value of cosine?
viva [34]
X^2 + y^2 = r^2
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cos(theta) = x/r = 15/17
Letter B
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