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dsp73
3 years ago
5

In a carton of 12 eggs, 2 are rotten. if we pick 4 eggs to make an omelet, what is the probability that we do not get a rotten e

gg?
Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0
IN THE GIVEN CARTON 10  EGGS ARE OKAY AND 2 ROTTEN .WE ARE REQUIRED TO SELECT 4 OKAY  EGGS.THIS CAN BE DONE IN 10C4 WAYS=210 WAYS
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Answer:120 units

Step-by-step explanation:

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3 years ago
Which of these relations on{0,1,2,3}are partial orderings? Determine the properties of a partial ordering that the others lack.
omeli [17]

Step-by-step explanation:

A = {0,1,2,3}

a): R = {(0,0),(2,2),(3,3)}

R is antisymmetric, because if the (a,b)∈R, than a=b.

R is not reflexive, because (1,1) ∉ R while 1 ∈ A.

R is transitive, because if the (a,b)∈R and (b, c) ∈ R, than a=b=c and (a,c)=(a,a)∈R.

R is not portable ordering because R is not reflexive.

b): R = {(0,0),(1,1),(2,0),(2,2),(2,3),(3,3)}

R is antisymmetric, because if the (a,b)∈R and if the (b, a) ∈ R, than a=b (since (2,0) ∈ R and (0,2) ∉ R; and (2,3) ∈ R and (3,2) ∉ R )

R is reflexive, because (a,a) ∈ R of every element a ∈ A.

R is transitive , because if the (a,b)∈R and if the ( b , c )∈R . then a = b or b = c ( since there are only two element not of the form ( a , a ) and that pair does not satisfy ( a,b ) ∈ R and ( b , a ) ∈ R ), which implies ( a , c ) = ( b , c ) ∈ R or ( a , c ) = ( a , b ) ∈ R.

R is a partial ordering, because R is reflexive, antisymmetric and transitive.

c): R =  {(0,0),(1,1),(1,2),(2,2),(3,1),(3,3)}

R is reflexive, because (a,a)∈R of every element a ∈ A.

R is antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R . then a = b ( since ( 1 , 2 )∈R and ( 2 , 1 ) ∉ R; ( 3 , 1 ) ∈ R and ( 1 , 3 ) ∉ R ).  

R is not transitive , because ( 3 , 1 ) ∈ R and ( 1 , 2 )∈R, while ( 3 , 2 ) ∈ R.

R is not a partial ordering. because R is not transitive .

d): R =  {(0,0),(1,1),(1,2),(1,3),(2,0),(2,2),(2,3), (3,0),(3,3)}

R is the reflexive, because ( a , a )∈R of every elements∈A.

R is the antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R, then a = b ( since ( 1 . 2 )∈R and ( 2 . 1 )∉R; similarly, all other elements not of the form (a,a) ).

R is not transitive, because ( 1 , 2 )∈R and ( 2 , 0 )∈R, while ( 1 . 0 )∉R.

R is not a partial ordering, because R is not transitive,

e):  R = { ( 0 , 0 ) , ( 0, 1 ) , ( 0 , 2 ) , ( 0 , 3 ) , ( 1 , 0 ) , ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 2 , 0 ) , ( 2 , 2 ) , ( 3 , 3 ) }

R is the reflexive , because ( a , a )∈R of every element a∈A .

R is not antisymmetric, because ( 1 , 0 )∈R and ( 0 , 1 )∈R while 0 is not equal to 1.

R is not transitive, because ( 2 , 0 )∈Rand ( 0 , 3 )∈R, while ( 2 , 3 )∉R .

R is not a partial ordering, because R is not the antisymmetric and not the transitive.

3 0
3 years ago
a six sided die is rolled 4 times in a row. What is the probability of getting 4 only on the last trial of this experiment?
hoa [83]
First, start of by saying what the probability of getting a 4 is, which is 1/6.
Now, this means the probability of not getting a 4 is 1-(1/6)=(5/6), since the total probability is 1.

After doing this, you should think about what it means to only get 4 on the last trial, the 4th trial.  It means that the probabilities of the 1st, 2nd, and 3rd trial were (5/6) each.  The 4th trial had a probability of (1/6).  So the probability would be calculated as following: ((5/6)^3*(1/6)=5^3/6^4.  You can use a calculator or your computer to find out that the probability is 125/1296.  

I hope this was helpful!
5 0
3 years ago
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s344n2d4d5 [400]

Answer: y=\frac{5-9x}{2}

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Step-by-step explanation:

9x + 2y = 5; y

9x-9x+2y = 5-9x

2y=5-9x

y=\frac{5-9x}{2}

1/15s - 2/3t = -2; s

(1/15s - 2/3t = -2)*15     ==> Get rid of fraction by multiplying both sides by 15

s - 30/3 t=-30

s-10t=-30

s=-30+10t

5 0
2 years ago
Jessica doesn't have any idea of what the answer is on one of her multiple choice questions like this problem. The problem has 4
leva [86]
Random probability, if that’s an answer.
8 0
3 years ago
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