Question

An experiment requires 54.6 g of ethylene glycol, a liquid whose density in SI units is 1114 kg/m3. Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in milliliters of the liquid should be used?

Answer 1

Answer: 49.0 cm^3

Explanation:

1) formula: density = mass / volume

=> volume = mass / density

2) mass (given) = 54.6 g

3) density (given) = 1114 kg / m^3

conversion of units: 1114 kg/ m^3 * 1000 g/kg * 1 m^3 / (1,000,000 cm^3) = 1.114 g/cm^3

4) calculation:

volume = 54.6 g / 1.114 g/cm^3 = 49.0 cm^3

Answer 2

Answer:

Volume in milliliters of the liquid should be used is 49 mL.

Explanation:

Mass of the ethylene glycol = 54.6 g = 0.0546 kg

Density = $1114 kg/m^3$

Volume of ethylene gylcol = V

$Density=\frac{Mass}{Volume}$

$1114 kg/m^3=\frac{0.0546 kg}{V}$

$V=\frac{0.0546 kg}{1114 kg/m^3}=4.90\times 10^{-5} m^3$

$1 m^3=1000 L$

$4.90\times 10^{-5} m^3=4.90\times 10^{-5}\times 1000=4.90\times 10^{-2} L=49 ml$

1 L = 1000 mL

Volume in milliliters of the liquid should be used is 49 mL.