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Sergio [31]
3 years ago
10

Please Help!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Vlada [557]3 years ago
3 0

Answer:

y = √(55).

Step-by-step explanation:

Triangles ADC and DBC are similar, so we have

(6+5) / y = y / 5

11/y = y/5

y^2 = 55

y = √(55).

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Can someone help me with these 3 plzzzz
aivan3 [116]
1 is 110. 2 is 65 and 3 is 35. You have to double 55 for the first question. For 2 you divide 2 from 130. And the third one shows the angle.
3 0
3 years ago
1) m - 38 = -44 * m = --6 o m = 6 m = 82 O m = --82​
galina1969 [7]

m-38=-44

    +38     +38       add 38 on both sides, solve for -44 + 38 which is -6.

__________

m = -6, is your final answer.

hope this helps :)

8 0
3 years ago
Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are asfollows:S
Thepotemich [5.8K]

Answer and explanation:

Given : Strands Copper wire from a manufacturer are analyzed forstrenghth and conductivity. The Results from 100 strands are as follows :

                                                 Strength Strength

                                                    High             Low

High conductivity                         74                8

Low conductivity                         15                3

To find :

a) If a stand is randomly selected, the probability that is conductivity is high and its strength is high

The favorable outcome is 74

The probability is given by,

P=\frac{74}{100}=0.74

b) If a stand is randomly selected, the probability that its conductivity is low or  strength is low

Conductivity is low A= 15+3=18

Strength is low B= 8+3=11

Conductivity is low and  strength is low A\cap B=3

Probability is given by,

P(A\cup B)=P(A)+P(B)-P(A\cap B)

P(A\cup B)=\frac{18}{100}+\frac{11}{100}-\frac{3}{100}

P(A\cup B)=0.18+0.11-0.03

P(A\cup B)=0.26

c) Consider the event that a strand low conductivity and the event that the strand has a low strength. Are these tow events mutually exclusive?

Since the events the stand has low conductivity and the stand has low strength  are not mutually exclusive, since there exists some cases in which both the  events coincide. i.e. Intersection of both the events exists with probability 0.03.

8 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
IM GIVING AWAY 20 POINTS!!!
SOVA2 [1]

Answer:

D. To provide a contrast to the actual enormity of the Biltmore

Step-by-step explanation:

Usually, when something is in "quotes", it's used to indicate sarcasm, emphasis, or a direct quote. This indicated emphasis.

6 0
3 years ago
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