Let
. The tangent plane to the surface at (0, 0, 8) is

The gradient is

so the tangent plane's equation is

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by
, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

or
,
, and
.
(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)
Standard form for the equation of the line is

Solution:
Given point is (2, –5).
slope of the line m = 
Here, 
Equation of a line passing through the point:




Subtract 15 from both sides of the equation.


Standard form for the equation of the line is

<u>Answer:</u>
Lamar will charge
to the comic dealer for a comic book.
<u>Solution:</u>
It is given that lamar purchases a comic book for
. He then marks up the price of a comic book by
which means he increases the price of the book by
and then sells it to the comic dealer.
We have to find out how much will he charge the comic book dealer.
New price of the book after lamar marks up the price is given by
New price 
=

Thus, lamar will charge
to the comic dealer for a comic book.
9514 1404 393
Answer:
5) 112°
6) 40°
Step-by-step explanation:
5) The angle E or ? is half the sum of the intercepted arcs:
? = (130° +94°)/2 = 112°
__
6) The angle D is half the difference of the intercepted arcs:
? = (135° -55°)/2 = 40°