Find the center and the radius of the circle x^2+y^2+6x-4y-12=0 show your work
1 answer:
Answer:
see explanation
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
To obtain this form use the method of completing the square on both the x and y terms
rearranging
x² + 6x + y² - 4y = 12
x² + 2(3)x + 9 + y² + 2(- 2)y + 4 = 12 + 9 + 4
(x + 3)² + (y - 2)² = 25 ← in standard form
with centre = (- 3, 2) and r = = 5
You might be interested in
I would have each block be 1/6 of a yard
You could technically have any value you want, but for me 1/6 is easiest because 1/2 and 1/3 will scale up to this like so
1/2 = (1/2)*(3/3) = 3/6
1/3 = (1/3)*(2/2) = 2/6
The diagram below might help if you're still stuck on why I picked 1/6.
