ANSWER:
mean:47.8
mode:57
median:45
37, 38, 43, 45, 57, 57, 58
Okay I don’t think I have to do it anymore I
Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
Answer:
<span>(−2, 3), because both lines pass through this point
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</span>hope that helps
change
given you
making x the subject by transferring the -19 to the right hand side of the equation
dividing through by 5
{
}
also given
change the operation sign to =
dividing through by -4
so the truth set is
{x:x>9/4}.
The < sign changes to > because we divided by a negative number when solving for x
