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mixer [17]
2 years ago
8

M little sister needs help with a geometry problem

Mathematics
1 answer:
Svetllana [295]2 years ago
6 0

Answer:

Segment bisector = KL

IJ = 11⅓

Step-by-step explanation:

Segment KL cuts segment IJ into two equal parts. Therefore the segment bisector of IJ is said to be segment KL.

Length of IJ:

From the figure given, the bisector divided the IJ into two equal parts. 1 part is given as 5⅔, therefore, the 2 parts joined together will give us lenght of IJ.

Thus, IJ = 2*5⅔ = 2 * 17/3 = 34/3 = 11⅓

Segment bisector = KL

IJ = 11⅓

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A water tank is box shaped with a square base of side length 5 ft. The tank is fed by a pipe above and drains from its base. In
adell [148]

Answer:

dy/dt = - (1/5) ft/s = - 0.2 ft/s

Step-by-step explanation:

Given

L = 5 ft

Qin = 25 ft³/s

Qout = 30 ft³/s

h = 10 ft

dy/dt = ?

We can apply the relation

ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s

⇒ ΔQ = - 5 ft³/s

Then we use the formula

Q = v*A

where Q = ΔQ, A = L²  is the area of square base and v = dy/dt  is the rate of change in the depth of the solution in the tank

⇒ ΔQ = (dy/dt)*L²

⇒ dy/dt = ΔQ/L²

⇒ dy/dt = (- 5 ft³/s)/(5 ft)²

⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s

6 0
3 years ago
the providence children muesuem installed a fence around the perimeter of the propety. the propety is a rectangle. one side is 3
mash [69]
Its a rectangle so two sides are equal and both sides that are opposite of each other are equal. So two sides are 37. Then you add them together to get 74, then subtract it from 164 to get 90 the rest of the fence length. Then divide it by two to get 45 which is the other side lengths, so it would be a 37 by 45 rectangle one side would be 37 while the other two are 45.
7 0
3 years ago
I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av
son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total  Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour           distance = 15miles

Time taken = distance / speed

                   = 15/25= 0.6 hours

2)  From Daska to Sialkot

speed= 40miles/hour           distance = 15miles

Time taken = distance / speed

                   = 40/15= 2.67 hours

3 ) From  Sialkot to Daska

speed= 30miles/hour           distance = 15miles

Time taken = distance / speed

                   = 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours

Speed = Total  Distance / Total Time

Speed= 45/ 5.3

          = 8.49=8.5 miles per hour

The average speed of the entire trip is 8.5 miles per hour.

7 0
2 years ago
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GalinKa [24]

Answer:

A) it is constant

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C) y-intercept=4

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2 years ago
A license plate is to consist of 5 digits followed by 5 uppercase letters. Determine the number of different license plates poss
EastWind [94]

Answer:

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Step-by-step explanation:

We are given that a license plate consist of 5 digits and 5 uppercase letters

Digits used=0,1,2,..9

Total number of letters=26

Repetition is not allowed

Total number of odd digits=(1,3,5,7,9)=5

The first place filled by 5

Second place filled by 4

Third place filled by 8

Fourth place filled by 7

Fifth place filled by 6

Sixth place filled by 26

Seventh place filled by 25

Eighth place filled by 24

Ninth place filled by 23

Tenth place filled by 22

Total number of possible  different license plates =5\times 4\times 8\times 7\times 6\times 26\times 25\times 24\times 23\times 22=5.3044992\times 10^{10}

7 0
3 years ago
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