Answer:
CORRECTED QUESTION:
Two cities have nearly the same north-south line of 110 degrees Upper W. The latitude of the first city is 23 degrees Upper N, and the latitude of the second city is 36 degrees N. Approximate the distance between the cities if the average radius of Earth is 6400 km.
ANSWER: 1452.11 km
Step-by-step explanation:
Since the two cities both lies on the Northern latitude of the sphere along the same longitude, we are going to subtract the angles the latitude that each city subtend at the equator.
36 - 23 = 13 degrees i.e the angles between the with two cities on a cross section the large circle formed by the longitude and its center.
Applying the formula for the length of an arc on a sector on the large circle
(∅/ 360) x 2πR
where, ∅ = is the angle between the two cities
R = radius of the Earth.
13/360 x 2 x π x 6400 = 1452.11 km
Answer:
THEY messed you upon this one and I don't see if you have to write or not!
More details please and thank you!
Step-by-step explanation:
Per 1 yard the cost would be $0.38. Not sure what unit you need it in, but thats the answer in yards.
Answer:
Therefore 'x' is equal to 65.4°
Step-by-step explanation:
In Right Angle Triangle ABC
∠ B = 90°
AC = Hypotenuse = 12
CB = Adjacent Side = 5
To Find:
∠ C = x
Solution:
In Right Angle Triangle ABC Cosine Identity we have
Substituting the values we get
Therefore 'x' is equal to 65.4°
Original Perimeter = 2.5 + 2.5 + 1.5 + 1.5 = 8
The longer dimension is 2.5 as 2.5 > 1.5To make 2.5 into 10, we must multiply by 4For the smaller length, we must also multiply by 41.5 x 4 = 6
New Perimeter = 10 + 10 + 6 + 6 = 32
Now find the difference between the old and the new perimeter32 - 8 = 24
<em>*No units were specified - if included, remember to put them in your answer.</em>
