Question

Enter the amplitude of the function f(x) . f(x)=3/4cos(3x)+4

Answer 1

ANSWER

$\frac{3}{4}$

EXPLANATION

The given function is

$f(x) = \frac{3}{4} \cos(3x) + 4$

This function is of the form:

$y = a \cos(bx + c) + d$

where |a| is the amplitude of the function.

Since

$a = \frac{3}{4}$

$| \frac{3}{4} | = \frac{3}{4}$

Hence, the amplitude of the given cosine function is ¾.

Answer 2

Answer:

The amplitude is $\frac{3}{4}$

Step-by-step explanation:

Let f(x) be a sinusoid function that has the following format:

$f(x) = bsin(wx + s) + h$

Then b is the amplitude of the function

h is the vertical displacement of the wave

s is the phase angle

$\frac{2\pi}{w}$ is the period.

In this problem $f (x) = \frac{3}{4}cos(3x) +4$

Then $\frac{3}{4} = b$

Therefore the amplitude of the function is $\frac{3}{4}$

The amplitude is a measure of the vertical size of the sinx wave