All categories

4 years ago

Area and Perimeter of L Shapes Help answer

Mathematics

1 answer:

victus00 [196]4 years ago

7 0

for perimeter you need to add, 15ft, 80ft, 30ft, 50ft, and 60ft which is 235 feet

for area you need to multiply 15ft times 80ft to get the area of the long verticle one which is 1200

then multiply 50ft times 30ft which is 1500

then add 1200 and 1500 which is 2700ft^2

You might be interested in

What is the value of t in this equation?<br> ()-

Alenkinab [10]

Answer:

Step-by-step explanation:

3 0

3 years ago

Mr. Hart is hanging a picture on a wall. the picture frame has a length of 13 inches and a width of 9 inches. how much wall spac

Bumek [7]

I believe what we are looking for is area. If so the formula for area of a rectangle is area equals width times length
A=wl

So:

9*13=117

The area would be 117, the amount of wall space needed is 117.

Hope this helps:)

5 0

3 years ago

I meeeed helppppppppppp

True [87]

I think the answer is B

4 0

3 years ago

The probability that a certain make of car will need repairs in the first seven months is 0.9. A dealer sells three such cars. W

aleksandr82 [10.1K]

Answer:

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they will require repair in the first seven months, or they will not. The probability of a car requiring repair in the first seven months is independent of other cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain make of car will need repairs in the first seven months is 0.9.

This means that $p = 0.9$ A dealer sells three such cars.

A dealer sells three such cars.

This means that $n = 3$

What is the probability that at least one of them will require repairs in the first seven months?

Either none will require repairs, or at least one will. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X > 0) = 1$

We want P(X > 0). So

$P(X > 0) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.9)^{0}.(0.1)^{3} = 0.001$

Then

$P(X > 0) = 1 - P(X = 0) = 1 - 0.001 = 0.9990$

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

4 0

3 years ago

What is the perimeter of this shape?

Zinaida [17]

WHat shape? Perimeter is all of the sides added together, so to find out. we would need to see the shape and its dimensions

7 0

4 years ago

Read 2 more answers