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Setler79 [48]
3 years ago
8

Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next

to each other. Mrs. Johnson's space will be longer, but it will have the same width as Mr Wei's space. Ms. Johnson has 48 carpet squares. Mr Wei has 36 carpet squares. Use distributive property to find the possible whole number dimension of the classes' total exhibition space. Explain what each number means in your expressions.
I may have found the answer but I am not sure.
Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

explain

Step-by-step explanation:

Nat2105 [25]3 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3

All common factors are 1, 2, 3, 4, 6, 12

<u>All possibilities:</u>

1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

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Hello from MrBillDoesMath!

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Discussion:

This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers:  11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of  3 consecutive primes.   I went back to my list of primes,  added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on  43, 47, and 53!

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