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prohojiy [21]
3 years ago
14

HELP PLEASE will give BRAINLIST

Mathematics
2 answers:
Zanzabum3 years ago
7 0
Ask the way on the top, (8-6) is not 2, it’s 4
Nataliya [291]3 years ago
6 0

Answer:

Step 3

Step-by-step explanation:

The exponents haven't been solved right.

For powers when multiple you add them together

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Which represents the polynomial below written in standard form?
STALIN [3.7K]

Answer:

B. 4x^3}+\frac{x^2}{2}-3x+6

Step-by-step explanation:

The polynomial is \frac{x^2}{2}-3x+4x^3}+6

To write in Standard form, the greatest exponent goes first, down to the least.

The greatest exponent is 3, so 4x^3 goes first.

4x^3}+\frac{x^2}{2}-3x+6 is what you end up with

6 0
2 years ago
Read 2 more answers
Please solve thank you
topjm [15]

Answer:

you multiply

Step-by-step explanation: itss easy just multiply it

5 0
3 years ago
Hey there please help me with this question
olga_2 [115]

Answer:

see explanation

Step-by-step explanation:

sum the parts of the ratio, 2 + 1 = 3 parts , thus

81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio

2 parts = 2 × 27 = 54 cm²

Area of A = 54 cm² and area of B = 27 cm²

The side of the original square = \sqrt{81} = 9 cm

The width of both rectangles is 9 cm ( width remains unchanged after cut )

Thus

Rectangle A

9 × length = 54 ( divide both sides by 9 )

length = 6 cm

Rectangle B

9 × length = 27 ( divide both sides by 9 )

length = 3 cm

Rectangle A → length = 6 cm, width = 9 cm

Rectangle B → length = 3 cm , width = 9 cm

5 0
3 years ago
Read 2 more answers
Please answer this question now
Sloan [31]

Answer:

<h2>             39°</h2>

Step-by-step explanation:

A radius to the tangent point always forms a right angle with the tangent:

m∠XWY = 90°

So:

  90° + 58° + x - 7° = 180°

    141° + x = 180°

        x = 39°

4 0
3 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
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