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podryga [215]
2 years ago
14

Change y=e^(-x^2) to x=

Mathematics
1 answer:
11111nata11111 [884]2 years ago
7 0
\bf y=e^{-x^2}\impliedby \textit{let's take \underline{ln} to both sides}\\\\
-------------------------------\\\\
\textit{Logarithm Cancellation Rules}\\\\
log_{{  a}}{{  a}}^x\implies x\qquad \qquad 
{{  a}}^{log_{{  a}}x}=x\\\\
-------------------------------\\\\
ln(y)=ln(e^{-x^2})\iff log_e(y)=log_e(e^{-x^2})\implies log_e(y)=-x^2
\\\\\\
-ln(y)=x^2\implies \sqrt{-ln(y)}=x
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To find the quotient of 8 :- 1/3, multiply 8 by
MrMuchimi

Answer:

3

Step-by-step explanation:


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What is the exponential notation of 100
Andreyy89
The answer is 1x10^2 or just simply 10^2.
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find the height of the cylinder below whose volume is approximately 1000 cubic inches use 3.14 for pi round your answer to the n
gtnhenbr [62]

Answer:

h = 1000 / (3.14)(r²)

Step-by-step explanation:

Given in the question,

volume of cylinder = 1000 inches³

Formula to use

V = πr²h

where V = volume

           π = 3.14

           r = radius

           h = height

1000 = (3.14)(r²)(h)

h = 1000 / (3.14)(r²)

               

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3 years ago
The given value below figure find the value of x
tino4ka555 [31]

Answer:

<h2>x = 117°</h2>

Step-by-step explanation:

We know:

The sum of the quadrilateral angles measures 360°.

Therefore we have the equation:

30^o+39^o+48^o+m\angle D=360^o\qquad(1)

The sum of angles x and D is equal to 360°. Therefore we have the other equation:

x+m\angle D=360^o\qquad(2)

From (1) and (2) we have:

x+m\angle D=30^o+39^o+48^o+m\angle D\qquad\text{subtract}\ m\angle D\ \text{from both sides}\\\\x=30^o+39^o+48^o\\\\x=117^o

6 0
3 years ago
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
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