1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrezito [222]
3 years ago
13

Modify the NumberedList class we implementd during the lecture by adding a member function: void NumberedList::insertPosition(in

t num, int pos) for inserting a new item at a specified position. A position of 0 means that the value will become the first item on the list, a position of 1 means that the value will become the second item on the list, and so on. A position equal to or greater than the length of the list means that the value is placed at the end of the list.
Computers and Technology
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

Check the explanation

Explanation:

#include<iostream>

using namespace std;

class LinkedList

{

private:

   // Declare a structure for the list.

   struct ListNode

   {

   int value;        // The value in this node.

   struct ListNode *next;// To point to the next node.

   };

   ListNode *head;        // List head pointer.

public:

   // Constructor.

   LinkedList()

       { head = NULL; }

   

   // Destructor

   ~LinkedList();

   

   // Linked list operations.

   void appendNode( int );

   void insertNode( int );

   void insertNodeAt(int,int);

    void deleteNode( int );

   void Reverse();

   void deleteAt(int);

   int Search(int);

   void display() const;

};

// appendNode appends a node containing the      

// value passed into num, to the end of the list.  

void LinkedList::appendNode( int num )

{

  ListNode *newNode; // To point to a new node.

  ListNode *nodePtr; // To move through the list.

  // Allocate a new node and store num there.

  newNode = new ListNode;

  newNode->value = num;

  newNode->next = NULL;

  // If there are no nodes in the list.

  // make newNode the first node.

  if ( !head )

     head = newNode;

  else // Otherwise, insert newNode at end.

  {

     // Initialize nodePtr to head of list.

     nodePtr = head;

     // Find the last node in the list.

     while ( nodePtr->next )

        nodePtr = nodePtr->next;

     // Insert newNode as the last node.

     nodePtr->next = newNode;

  }    //    end else-if

  display();  

}    //    end function appendNode

// displayList shows the value stored in each              

// node of the linked list pointed to by head.      

                       

void LinkedList::display() const

{

   ListNode *nodePtr; // To move through the list

   if ( !head )

   {

       cout << "\n\tThe list is empty.";

       return;

   }

   // Position nodePtr at the head of the list.

   nodePtr = head;

   cout << "\n\n\tThe elements in the list are:\n\t";

   // While nodePtr points to a node, traverse the list.

 

    while (nodePtr)

   {

       // Display the value in this node.

       cout << nodePtr->value << " -> ";

       // Move to the next node.

       nodePtr = nodePtr->next;

   }    //    end while.

   cout << "Null";

}    //    end function displayList.

// Reverse function re-arranges node in the list.

void LinkedList::Reverse()

{

   ListNode *nodePtr;

   ListNode *next;

   ListNode *result=NULL;

   if ( !head )

   {

       cout << "\n\tThe list is empty.";

       return;

   }

   // Position nodePtr at the head of the list.

   nodePtr = head;

   while (nodePtr!=NULL)

   {

       next=nodePtr->next;

       nodePtr->next=result;

       result=nodePtr;

       nodePtr=next;

   }

   head=result;

display();

}

// The insertNode function inserts a node with num copied to its value member.                

void LinkedList::insertNode( int num )

{

   ListNode *newNode;             // A new node.

   ListNode *nodePtr;             // To traverse the list.

   ListNode *previousNode = NULL; // The previous node.

   // Allocate a new node and store num there.

   newNode = new ListNode;

   newNode->value = num;

   newNode->next = NULL;

 

   // If there are no nodes in the list make newNode the first node.

   if ( !head )

       head = newNode;

   else // Otherwise, insert newNode.

   {

       // Position nodePtr at the head of list.

       nodePtr = head;

       //    Initialize previousNode to NULL.

       previousNode = NULL;

       //    Skip all nodes whose value is less than num.

       while ( nodePtr != NULL && nodePtr->value < num )

       {

           previousNode = nodePtr;

           nodePtr = nodePtr->next;

       }

       //If the new node is to be the 1st in the list,

       //    insert it before all other nodes.

       if ( previousNode == NULL )

       {

           head = newNode;

           newNode->next = nodePtr;

       }

       else // Otherwise insert after the previous node.

       {

           previousNode->next = newNode;

           newNode->next = nodePtr;

       }

   }    //    end else-if

     

display();  

}    //    end function insertNode.

// The insertNode function inserts a node at pos  

//with num copied to its value member.          

void LinkedList::insertNodeAt( int num ,int pos)

{

   ListNode *newNode;             // A new node.

   ListNode *nodePtr;             // To traverse the list.

   ListNode *previousNode = NULL; // The previous node.

   int i=0;

   // Allocate a new node and store num there.

   newNode = new ListNode;

   newNode->value = num;

   newNode->next = NULL;

   // Position nodePtr at the head of list.

       nodePtr = head;

   if(pos==0)//to inserted at first.

   {  

       newNode->next=head;

       head=newNode;

   }

   else

   {

   while(nodePtr != NULL && i<pos) //loop to reach position.

       {  

           previousNode=nodePtr;

           nodePtr=nodePtr->next;

           i++;

       }

       if(nodePtr==NULL)//position not found.

           cout<<"Invalid Position :"<<endl;

       else//inserts node.

       {

           newNode->next=nodePtr;

           previousNode->next=newNode;

       }

   }

   display();

}

//    The deleteNode function searches for a node with num as its value.  

//The node, if found, is deleted from the list and from memory.

void LinkedList::deleteNode( int num )

{

   ListNode *nodePtr;       // To traverse the list.

   ListNode *previousNode;//To point to the previous node.

   // If the list is empty, do nothing.

   if ( !head )

   {

       cout << "\n\tFailed to delete as list is empty.";  

       return;

   }

   // Determine if the first node is the one.

   if ( head->value == num )

   {

       nodePtr = head->next;

       delete head;

       head = nodePtr;

   }

   else

   {

       // Initialize nodePtr to head of list.

       nodePtr = head;

       // Skip all nodes whose value member is not equal to num.

       while (nodePtr != NULL && nodePtr->value != num)

       {

           previousNode = nodePtr;

           nodePtr = nodePtr->next;

       }

You might be interested in
The term used for doing business online is referred to as ___.
liubo4ka [24]
The process for doing business online is referred to as e-commerce.
6 0
3 years ago
A _____________ is used to make a deep copy of an object.
lesya [120]
The answer is a 3D Printer
3 0
4 years ago
In which year was chip used inside the computer for the first time?? ​
AfilCa [17]

the first chip was invented in 1975

hope this help!

5 0
3 years ago
Read 2 more answers
. Reorder the following efficiencies from smallest to largest:
alexdok [17]

Answer:

The order of the efficiencies is as following:-

10,000 < 2n < nlog(n) < n5 < n!.

Explanation:

10,000 is constant time whatever will be the size of the problem the efficiency will remain the same.

2n this efficiency is linear it will grow proportionally as the size of the problem increases.

nlog(n) this efficiency is is a bit greater than 2n though it will grow faster than 2n but slower than n2 as the size of the problem increases.

n5 this efficiency is very poor.It is growing very rapidly as the size of the problem increases.

n! is the worst efficiency of them all.

n!=n*(n-1)*(n-2)*(n-3)*(n-4)*.......2*1.

It will grow beanstalk in jack and the beanstalk.

3 0
3 years ago
which of these tools stick to the edge of an image, thus making it easy to select the shape of an image
USPshnik [31]

Answer:

ljb lih lug outbpiyougvotvoy

outiyfiyfiyfiyffiyvitfurcutfcutcrcutfutcdu

Explanation:

didn't understand the question

3 0
3 years ago
Other questions:
  • Welcome to Cypres...
    6·1 answer
  • Which asset would be helpful in assessing a web or UI designer’s skills?
    13·2 answers
  • Which protocols are TCP/IP application layer protocols? (choose all that apply)
    5·2 answers
  • An employee believes there is an imminent danger situation at her workplace. She contacts OSHA to report the safety hazard. Her
    8·1 answer
  • 1. The number of major solutions for preventing workplace hazards is
    14·1 answer
  • What are all the folders located on the DOCK called?
    11·1 answer
  • Given a variable s associated with a str, write an expression whose value is a str that is identical except that all the letters
    15·1 answer
  • What is the full form of IE? ​
    9·1 answer
  • Complete the second clause of the following Prolog program for member/2 where member(X, Y) checks whether X is an element (a mem
    7·1 answer
  • 100 POINTS!!!!!!!!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!