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3 years ago

A number is between -5 and -14. What is the least possible integer value of the number?

1 answer:

3 0

Hello!

An integer can be positive, negative, or zero. Given this, the least possible integer value of a number between -5 and -14 is -13.

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Factor the expression using the GCF. 24y+88x =

Ne4ueva [31]

Answer:

4(6y + 22x)

Step-by-step explanation:

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3 years ago

Give an example of two numbers that both have six digits, it the greater number is determined by the hundreds place.

spayn [35]

Answer:

565,463 and 565,863

Step-by-step explanation:

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4 years ago

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

$f=z^3 -x^2y$

Firstly, we can find gradient

so, we will find partial derivatives

$f_x=0 -2xy$

$f_x=-2xy$

$f_y=0 -x^2$

$f_y=-x^2$

$f_z=3z^2$

now, we can plug point (-5,5,2)

$f_x=-2*-5*5=50$

$f_y=-(-5)^2=-25$

$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

4 years ago

Read 2 more answers

X+2y=3 <br> 3y+5y=7 <br> I dont know

Lena [83]

Answer:

Step-by-step explanation:

3y+5y=8y

8y=7(divide 8 in both sides to get y)

y=7/8

x+2y=3...but we already know the value of y, so substitute 7/8 to y

x+2(7/8)=3

x+14/8=3

x=3-14/8

=1.25

8 0

3 years ago

Look at the figure shown below:

kow [346]

Answer: b) two sides and the included angle are congruent

<u>Step-by-step explanation:</u>

RS = QS SIDES are congruent

∠PSR ≡ ∠PSQ ANGLES are congruent

PS = PS SIDES are congruent

ΔPSR ≡ ΔPSQ by the Side-Angle-Side (SAS) Congruency Theorem

Since we know the triangles are congruent, we can state that their parts are congruent:

Congruent-Parts of-Congruent-Triangles are-Congruent (CPCTC)

8 0

4 years ago